C++新手，我不明白"EXC_BAD_ACCESS"错误

我正在尝试将一个二维元胞自动机从Processing转换为openFrameworks(C++(。我已经为细胞和生命游戏功能编写了课程。应用程序成功构建，但立即崩溃，并出现以下错误：线程1:程序接收到信号："EXC_BAD_ACCESS"。

这是我的标题我的生活类游戏

#include "Cell.h"
class GoL {
public:
    GoL();
    void init();
    void generate();
    void display();
    void run();
    int w = 20;
    int cols;
    int rows;
    std::vector<vector<cell> > board;

};

这里是实现：

#include "GoL.h"
GoL::GoL() {
    cols = ofGetWidth() / w;
    rows = ofGetHeight() / w;
    board[rows][cols];
    init();
}
void GoL::run() {
    generate();
    display();
}
void GoL::init() {
    for (int i = 0; i < cols; i ++) {
        for (int j = 0; j < rows; j ++) {
            board[i][j] = *new cell(i * w, j * w, w);
        }
    }
}
void GoL::generate() {
    for (int i = 0; i < cols; i ++) {
        for (int j = 0; j < rows; j ++) {
            board[i][j].savePrevious();
        }
    }
    for (int x = 0; x < cols; x ++) {
        for (int y = 0; y < cols; y ++) {
            int neighbours = 0;
            for (int i = -1; i <= 1; i ++) {
                for (int j = -1; j <= 1; j ++) {
                    neighbours += board[(x + i + cols) % cols][(y + j + rows) % rows].previous;
                }
            }
            neighbours -= board[x][y].previous;
            // Rules of Life
            if      ((board[x][y].state == 1) && (neighbours <  2)) board[x][y].newState(0);
            else if ((board[x][y].state == 1) && (neighbours >  3)) board[x][y].newState(0);
            else if ((board[x][y].state == 0) && (neighbours == 3)) board[x][y].newState(1);          
        }
    }
}
void GoL::display() {
    for (int i = 0; i < cols; i ++) {
        for (int j = 0; j < rows; j ++) {
            board[i][j].display();
        }
    }
}

错误显示在vector.h文件、GoL头文件以及我在GoL实现中调用init((方法的地方。非常感谢您的帮助。