调用"会议：：会议()"没有匹配函数

no matching function for call to 'meetings::meetings()

本文关键字：会议 函数 调用      更新时间：2023-10-16

编程新手，但当我尝试创建此链接列表时，我收到一个错误"调用'meetings:：meetings（）'没有匹配函数"。我已经尝试了几次，但我不知道是什么原因导致了问题。

 class meetings{
 public:

   void duplicatetest (string,memberlist *&head);
   void menufn(memberlist *&head);
   void meetinginfo( memberlist *&head,string);
   string timestamp ( memberlist *&head,string);
   memberlist *&head;
   string UID;
   string timestp;
   meetings *timest;
   meetings *link;
   int meetnum;
   string dt;
 };


 void meetings::meetinginfo(memberlist *&head, string dt ){
   string meetingNum;
   memberlist *currptr;
   meetings  *meetptr , *nnmeet ,*meetcurr, *meethead;
   meethead= NULL;
   if (currptr->meetnum == 0 ) {
     meethead = new meetings; // <<<  Error appears here!
                meetingNum = currptr->UID;
     meethead->UID = meetingNum;                        
     meethead->timestp = dt;
     meetcurr=meethead;
     system ("pause");                        
   }
   else {
     nnmeet = new meetings;
     meetcurr->link= nnmeet;
     nnmeet->UID=currptr->UID;
     nnmeet->timestp = dt;
   }
   cout << "Meeting number : ";
   menufn(head);
 }


using namespace std;
#include "memberlist.h"
#include "meeting.h"
int main(){
  system("color f0");    
  memberlist *member,entermember;
  meetings menu, *meet;
  entermember.createlinklist(member);
  menu.menufn(member);
  system("pause");
  return 0;
}//End of main

这是我所指的会议类中的另一类

 class memberlist  {
  public:
  void createlinklist (memberlist *&head);
  void displaylist (memberlist *&head);
  memberlist *link;
  string name[2];
  string UID;
  int meetnum;

  };
 void memberlist::createlinklist (memberlist *&head)
 {
 ifstream fin;
 memberlist *currptr , *nnptr;
 head = NULL;

 fin.open ("members.txt");

 while (fin)
 {
       if(head==NULL)
       {
        head = new memberlist;
        fin>>head->UID >> head->name[0] >> head->name[1];
        head->meetnum = 0;
        currptr = head;           
       }
 nnptr = new memberlist;
 currptr->link = nnptr;

 fin>>nnptr->UID >> nnptr->name[0] >> nnptr->name[1];
 nnptr->meetnum = 0;
 currptr = nnptr;
 }

 currptr->link = NULL;
 currptr = NULL;

 displaylist(head);      
}
void memberlist::displaylist (memberlist *&head)
{
 //memberlist *meetptr;
 cout << " Student information " << endl;
 memberlist *currptr;
 currptr = head;
 //meetptr = meethead;

 while (currptr->link!= NULL)
 {
   cout << setw(10) << left << currptr->UID << " " << currptr->name[0] <<" " << 
           currptr->name[1] <<endl;
   currptr= currptr->link; 
 }
 }

问题是数据成员头被定义为引用。

memberlist *&head;

编译器无法生成默认构造函数，因为它不知道如何初始化引用。你必须自己定义构造函数。

根据C++标准

在以下情况下，类X的默认默认构造函数被定义为已删除：--任何不带大括号或相等初始值设定项的非静态数据成员都属于参考类型，

还要考虑referbces只能在ctor初始值设定项中初始化。例如

meetings::meetings( memberlist * &ptr ) : head( ptr )
{
   //  possible some additional code
}

或者正如我在类定义中引用的引号中所说的那样，使用大括号或等号初始值设定项。

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