C++线程错误:没有名为"类型"MINGW 的类型

我目前正在为我的操作系统类做一个项目，我必须制作一个程序来查找要在线程中运行的质数。

所以我这样做了：

#include <iostream>
#include <cmath>
#include <thread>
#define THREADNUMBER 100
using namespace std;

int CONTADOR = 0;
int CONTADORTHREADEXECUTADA = 0;
int primeRange(int v1, int v2) {
int a, limit;                        
bool isprime;
for (int i = v1; i <= v2; i++) {
if (i % 2 != 0 && i % 3 != 0) {
isprime = true;
limit = i / 2;
if(i == 1) isprime =false;

limit = (int)sqrt(i); //General case
for(a=2; a <= limit; a++){
if(i % i == 0 && i != 2){
isprime = false;
break;
}
}
if (isprime) {
CONTADOR++;
}
}
}
CONTADORTHREADEXECUTADA++;
return 1;
} 
int main(int argc, char *argv[ ] ) {
int number1 =  atoi(argv[1]);
int number2 = atoi(argv[2]);
int dif = number2-number1;
thread** vec = new thread*[THREADNUMBER];
cout<< "criando threads" <<endl;
int contadorthread = 0;
if (dif <= THREADNUMBER) {
for(int i = number1; i <= number2; i++) {
thread* t = new thread(primeRange(i,i));
vec[contadorthread] = t; 
contadorthread++;
}
} else {
int c = dif / THREADNUMBER;
for(int i = number1; i <= number2; i+=(c+1)) {
if (contadorthread==THREADNUMBER-1) {
thread* t = new thread(primeRange(i,number2));
vec[contadorthread] = t; 
contadorthread++;
break;
}
thread* t = new thread(primeRange(i,i+c));
vec[contadorthread] = t; 
contadorthread++;
}
cout<<contadorthread << " threads criadas"<<endl;
cout<<"inicializando threads" <<endl;
while (CONTADORTHREADEXECUTADA < contadorthread) {
cout<<contadorthread - CONTADORTHREADEXECUTADA << endl;
}
cout<< CONTADOR << "primos encontrados" <<endl;
} 
}

但是每次我尝试在 64 个窗口 GCC 上编译时，我都会收到此错误消息，指出没有名为"type"的类型

我用这个编译

g++ -Wall -g -std=c++11 -pthread codigo.cpp -o exe -Wall

我能做什么？ 我已经下载了他们说是线程安全的 mingw 版本。