在文件中查找多个单词，然后提取这些单词后面的值

注意：我问了一个类似的问题，但由于我没有提供代码（我想），这个问题被"搁置"了。现在我也写了代码，但我还面临一些其他问题。

从我的.bench文件中，我必须读取写入制动器()的值，这是我设法做到的。但问题是，我读取了INPUT、OUTPUT、NAND之后的制动器中的值。

.bench file

INPUT(1)
INPUT(2)
INPUT(3)
INPUT(6)
INPUT(7)
OUTPUT(22)
OUTPUT(23)
10 = NAND(1, 3)
11 = NAND(3, 6)
16 = NAND(2, 11)
19 = NAND(11, 7)
22 = NAND(10, 16)
23 = NAND(16, 19)

到目前为止，我已经编写了代码来查找INPUT、OUTPUT和NAND之后括号内的值，但可以看出，我正在一次又一次地重复类似的代码行那么，我如何推广相同的代码来查找OUTPUT、NAND等之后的值。

int Circuit::readBenchFile(string filename) //read the benchfile and generate inputs, outputs and gates accordingly
{
    //Reading the .bench file
    ifstream input_file;
    char * S = new char[filename.length() + 1];
    std::strcpy(S,filename.c_str());
    input_file.open(S);
    if(input_file.fail())
    {
        cout << "Failed to open Bench file.n";
        return 1;
    }
    ///////
string line;
string guard_str("#");
string input_str ("INPUT"), output_str ("OUTPUT"), nand_str("NAND");
while (getline( input_file, line ))  
{
    std::size_t guard_found = line.find(guard_str);
    if (guard_found ==std::string::npos)
    {
        ///Input
        std::size_t found = line.find(input_str);
        if (found!=std::string::npos)
        {
            found = line.find_first_of('(', found + 1);
            //Getting our input name and printing it.
            string out = line.substr( found + 1, ( line.find_first_of(')', found) - found - 1) );
            std::cout << out << std::endl;
        }
        ///Output
        std::size_t found1 = line.find(output_str);
        if (found1!=std::string::npos)
        {
            found1 = line.find_first_of('(', found1 + 1);
            //Getting our input name and printing it.
            string out = line.substr( found1 + 1, ( line.find_first_of(')', found1) - found1 - 1) );
            std::cout << out << std::endl;
        }       
        ///NAND
        std::size_t found_2 = line.find(nand_str);
        if (found_2!=std::string::npos)
        {
            found_2 = line.find_first_of('(', found_2 + 1);
            //find first input
            string first_input = line.substr( found_2 + 1, ( line.find_first_of(',', found_2) - found_2 - 1) );
            //Second input
            found_2 = line.find_first_of(',', found_2 + 2);
            string second_input = line.substr( found_2 + 1, ( line.find_first_of(')', found_2) - found_2 - 1) );
            cout<<"nInputs to NAND gate are:  "<<( first_input + string(" & ") + second_input );
        }           
    }
}           

}