nirq:标志不匹配irq80.00002083(ledtrig-gpio）对00000083(USER）

我正在SAMA5D27-SOM1-EK1板上做一些实验。我使用的是Linux操作系统。我正在利用我的板GPIOS。在GPIO 10处定义了RED LED，在GPIO 29中定义了USER按钮。我写了C++程序来控制电路板的LED，这里是代码：

#include<iostream>
#include<fstream>
#include<string>
using namespace std;
#define LED0_PATH "/sys/class/leds/red"
void removeTrigger(){
// remove the trigger from the LED
std::fstream fs;
fs.open( LED0_PATH "/trigger", std::fstream::out);
fs << "none";
fs.close();
}
int main(int argc, char* argv[]){
if(argc!=2){
cout << "Usage is makeLED and one of: on, off, flash or status"
<< endl;
cout << "e.g. makeLED flash" << endl;
}
string cmd(argv[1]);
std::fstream fs;
cout << "Starting the LED flash program" << endl;
cout << "The LED Path is: " << LED0_PATH << endl;

// select whether it is on, off or flash
if(cmd=="on"){
removeTrigger();
fs.open (LED0_PATH "/brightness", std::fstream::out);
fs << "1";
fs.close();
}
else if (cmd=="off"){
removeTrigger();
fs.open (LED0_PATH "/brightness", std::fstream::out);
fs << "0";
fs.close();
}
else if (cmd=="flash"){
fs.open (LED0_PATH "/trigger", std::fstream::out);
fs << "timer";
fs.close();
fs.open (LED0_PATH "/delay_on", std::fstream::out);
fs << "50";
fs.close();
fs.open (LED0_PATH "/delay_off", std::fstream::out);
fs << "50";
fs.close();
}
else if (cmd=="status"){
// display the current trigger details
fs.open( LED0_PATH "/trigger", std::fstream::in);
string line;
while(getline(fs,line)) cout << line;
fs.close();
}
else{
cout << "Invalid command" << endl;
}
cout << "Finished the LED flash program" << endl;
return 0;

这似乎很好：当我录制./target_bin off时，红色Led熄灭，on和flash命令也是如此。

但当我试图用BUTTON(USER/GPIO 29)控制LED(RED/GPIO 10)时，我添加了这部分代码：

else if (cmd=="button"){
removeTrigger();
fs.open (LED0_PATH "/trigger", std::fstream::out);
fs << "gpio";
fs.close();
fs.open (LED0_PATH "/gpio", std::fstream::out);
fs << "29";
fs.close();
}

现在，当我录制./target_bin button时，它显示了一个错误：

nirq：标志不匹配irq80。00002083(ledtrig gpio)对00000083(用户)指示灯红色：request_irq失败，错误为-16

有人能帮我吗？