我有一个 Qt 对象的 2d 数组，我已经用值播种了这些对象。如何访问数组中特定对象的值并更改它们？

我的瓷砖.cpp文件是我尝试在rect[someint][someint]访问对象的地方，以便我可以使用我的ai来更改板上的棋子。现在，它是通过单击特定磁贴并传递该磁贴信息以验证移动是否正确来完成的。我遇到麻烦的是弄清楚如何更改磁贴，而无需通过单击访问它。

当我尝试更改 rect 的值时，例如 rect[someint][someint]->piece=0，我得到一个无效的类型未解析的重载函数类型 [int] 数组子矩形[tempy][tempx] 错误。

我在主函数上面的一些主文件：

Tile * rect[8][8];
void chessBoard(QWidget *baseWidget, Tile *rect[8][8]){
for(int i = 0; i < 8; i++){
boardX = 350;
for(int j = 0; j < 8; j++){
//seed tile array with tile objects
rect[i][j] = new Tile(baseWidget);
rect[i][j]->tileColor=(i+j)%2;
rect[i][j]->piece=0;
rect[i][j]->row=i;
rect[i][j]->col=j;
rect[i][j]->tileNum=k++;
rect[i][j]->tileDisplay();
rect[i][j]->setGeometry(boardX,boardY,64,64);
//rect[i][j]->setScaledContents(true);
boardX += 64;
}
boardY += 64;
}    

瓷砖的一小部分.cpp：

Pieces *isValid = new Pieces();
extern Tile * rect[8][8];
extern QWidget *myWidget;
Tile *click1;
void Tile::mousePressEvent(QMouseEvent * event){
moveChecking(this, ++count);
}
Tile::moveChecking(Tile *temp, int countC){

if(countC==1){
if(temp->piece && (temp->pieceColor==turns%2)){

if(temp->pieceName != " "){
tempx = temp->col;
tempy = temp->row;
click1 = new Tile();
temp->setStyleSheet("QLabel {background-color: green;}");
click1=temp;
} else {
count = 0;
}
} else {
count = 0;
}
} else {
if(temp->tileNum==click1->tileNum){
click1->tileDisplay();
count = 0;
} else {
//ready coordinates to give to Pieces
tempx = click1->col;
tempy = click1->row;
tempx2 = temp->col;
tempy2 = temp->row;
//give coordinates of piece origin and possible landing
isValid->coordinates(tempx, tempy, tempx2, tempy2);
//check if input coordinates are a valid move for piece and player
if(isValid->whichPiece() == true){
//switch Qwidget values on origin and spot piece landed
click1->piece=0;
temp->piece=1;
//give moved piece same attributes
temp->pieceColor=click1->pieceColor;
temp->pieceName=click1->pieceName;

click1->display(click1->pieceName);
temp->display(click1->pieceName);
click1->tileDisplay();
temp->tileDisplay();

turns++;
count = 0;
if(aiOn == 1){
aiTurn(temp);
}

} else {
count = 1;
}
}
}
}

在 ai 转弯处，我完全陷入了试图弄清楚如何在磁贴对象数组中的坐标 y、x 处访问给定图块的地方。感谢您的任何帮助！

人工智能功能。目前没有做我需要它做的事情，即更改 Gui 板上的棋子。我提到的错误出现在@@@符号上。

void Tile::aiTurn(Tile *temp){
int aiIsThinking = 1;
Ai_Logic *newMove = new Ai_Logic;
while(aiIsThinking == 1){
newMove->calculateBestMove();

//ready coordinates to give to Pieces
tempx = aiX;
tempy = aiY;
tempx2 = aiX1;
tempy2 = aiY1;
//give coordinates of piece origin and possible landing
isValid->coordinates(tempx, tempy, tempx2, tempy2);
//check if input coordinates are a valid move for piece and player
if(isValid->whichPiece() == true){

aiClick = new Tile();
//aiClick = &rect[tempy][tempx];
aiClick1 = new Tile();
rect[tempx][tempy]->pieceName = "P"; //@@@
//simulating ai clicking start piece
aiClick->row = tempx;
aiClick->col = tempy;
//aiClick->pieceColor = rect[tempx][tempy].pieceColor;
//simulating ai clicking landing spot
aiClick1->row = tempx2;
aiClick1->col = tempy2;
//tile color corrections
aiClick -> tileColor=(tempx+tempy)%2;
aiClick1 -> tileColor=(tempx2+tempx2)%2;

//switch Qwidget values on origin and spot piece landed
aiClick->piece=0;
aiClick->pieceName = " ";
aiClick1->piece=1;
//give moved piece same color at landing
for(int k = 0; k < 8; k++){
if(boardArr[tempy2][tempx2] == whitePieces[k]){
aiClick1->pieceColor=0;
} else if (boardArr[tempy2][tempx2] == blackPieces[k]){
aiClick1->pieceColor=1;
}
}

// aiClick1->pieceColor=aiClick->pieceColor;
aiClick1->pieceName=boardArr[tempy2][tempx2];
//display piece having moved
aiClick->display(aiClick->pieceName);
aiClick1->display(aiClick->pieceName);
//make sure tile color is correct
aiClick->tileDisplay();
aiClick1->tileDisplay();
turns++;
count = 0;
aiIsThinking = 0;
}
}
}