理性类和移动语义不起作用

我试图在问题中为已经给定的类(@Aak的答案)添加更多功能：如何输出分数而不是十进制数？ 用于打印numerator / denominator分数。

首先，给定的代码在代码中没有任何更改的情况下无法工作。然后我在进行一些更改后使其工作。但是，我的实现给了我错误的输出。

例如：

input: A = 3;
B = 3;
Output: 9/1
9
instead of: 1

以下是完整的实现：

#include <iostream>
/********************** Rational class **********************************/
class Rational
{
private:
int m_numerator, m_denominator;
private:
inline void simplificate()
{
int commondivisor = 1;
for(int i=2;i<= std::min(abs(m_numerator), abs(m_denominator));i++)
if( m_numerator%i == 0 && m_denominator%i == 0 )
commondivisor = i;
m_numerator /= commondivisor;
m_denominator /= commondivisor;
}
public:
Rational()                                  // Defualt
:m_numerator(1), m_denominator(1)
{}
Rational(const int& num, const int& den=1)  // Parameterized
:m_numerator(num), m_denominator(den)
{}
Rational(const Rational& other)             // Copy
:m_numerator(other.m_numerator), m_denominator(other.m_denominator)
{}
/*Rational(Rational&& other)                  // Move
:m_numerator(other.m_numerator), m_denominator(other.m_denominator)
{}*/
~Rational(){}
Rational& operator/ (const int& divisor)
{
m_denominator *= divisor;
simplificate();
return *this;
}
Rational& operator/ (const Rational &divisor)
{
m_numerator *= divisor.m_numerator;
m_denominator *= divisor.m_denominator;
simplificate();
return *this;
}
const double getrealformat()const
{
return  static_cast<double>(m_numerator)/
static_cast<double>(m_denominator);
}
friend double operator/ (Rational& obj, const int& divisor);
friend void printRational(Rational& obj, const int& A, const int& B);
friend void printRational(Rational& obj, const int&& A, const int&& B);
};
/************************** Friend functions ********************************/
double operator/ (Rational& obj, const int& divisor)
{
obj.m_denominator *= divisor;
obj.simplificate();
return obj.getrealformat();
}
void printRational(Rational& obj, const int& A, const int& B)   // lvalue
{
Rational r1(A), r2(B);
obj = r1/r2;
std::cout<<obj.m_numerator<<'/'<<obj.m_denominator<<std::endl;
std::cout<<obj.getrealformat()<<std::endl;
}
void printRational(Rational& obj, const int&& A, const int&& B)  // rvalue
{
Rational r1(A), r2(B);
obj = r1/r2;
std::cout<<obj.m_numerator<<'/'<<obj.m_denominator<<std::endl;
std::cout<<obj.getrealformat()<<std::endl;
}
/*****************************************************************************/
int main()
{
Rational obj;
printRational(obj, 3,3);
return 0;
}

问题 - 1：逻辑看起来不错，但我不知道为什么我得到错误的答案。有人能找到问题吗？

问题 - 2：我已经为类编写了"Move"构造函数，您可以在注释部分找到它。但是，由于以下错误，我无法使用它：

D:ProgrammingC++CPP ProgramsClass - FractionsClass - Fractions.cpp|70|error: use of deleted function 'Rational& Rational::operator=(const Rational&)'|
D:ProgrammingC++CPP ProgramsClass - FractionsClass - Fractions.cpp|77|error: use of deleted function 'Rational& Rational::operator=(const Rational&)'|

(据我所知，每当它被调用时，移动的对象/实例都会被销毁。

任何人都可以帮助我实现此类的 Move 构造函数吗？