更新功能(OpenFramework)中的Leap Motion Play声音
Leap motion play sound in update function (openframework)
我使用Leap Motion播放乐器音符,我使用棕榈置触发声音播放的声音,但这不是我想要的,棕榈点在更新功能中,声音将播放基于帧速率一遍又一遍地。太快了,我想要像鼠标向上和鼠标向下一样的跳跃运动...当棕榈置更换时,播放声音。这是我的代码
void ofApp::update(){
...
if (hands[i].palmPosition().z < 50) {
isTouch = true;
if ((hands[i].palmPosition().x > -240)&& (hands[i].palmPosition().x < -160)) {
pianoE.setVolume(1);
pianoE.play();
}
if ((hands[i].palmPosition().x >-120)&& (hands[i].palmPosition().x <-60)) {
pianoE.setVolume(1);
pianoE.play();
}
if ((hands[i].palmPosition().x >-20)&& (hands[i].palmPosition().x < 20)) {
pianoC.setVolume(1);
pianoC.play();
}
if ((hands[i].palmPosition().x > 90)&& (hands[i].palmPosition().x < 120)) {
pianoC.setVolume(1);
pianoC.play();
}
if ((hands[i].palmPosition().x >180)&& (hands[i].palmPosition().x < 240)) {
pianoC.setVolume(1);
pianoC.play();
}
}else{
isTouch = false;
}
...
}
您检查声音isPlaying()
是否尚未执行此操作。
,例如
if (hands[i].palmPosition().z < 50) {
isTouch = true;
if ((hands[i].palmPosition().x > -240)&& (hands[i].palmPosition().x < -160)) {
pianoE.setVolume(1);
if(!pianoE.isPlaying()) pianoE.play();
}
if ((hands[i].palmPosition().x >-120)&& (hands[i].palmPosition().x <-60)) {
pianoE.setVolume(1);
if(!pianoE.isPlaying()) pianoE.play();
}
if ((hands[i].palmPosition().x >-20)&& (hands[i].palmPosition().x < 20)) {
pianoC.setVolume(1);
if(!pianoC.isPlaying()) pianoC.play();
}
if ((hands[i].palmPosition().x > 90)&& (hands[i].palmPosition().x < 120)) {
pianoC.setVolume(1);
if(!pianoC.isPlaying()) pianoC.play();
}
if ((hands[i].palmPosition().x >180)&& (hands[i].palmPosition().x < 240)) {
pianoC.setVolume(1);
if(!pianoC.isPlaying()) pianoC.play();
}
}else{
isTouch = false;
}