即使我的函数全部定义,也会在C 中获得不确定的引用

Getting an undefined reference to error in c++ even though I have the functions all defined

本文关键字:不确定 引用 函数 我的 全部 定义      更新时间:2023-10-16
enum state{
state_Mmenu,    // State 0
state_settingmenu,      // State 1
state_gamemenu,     // State 2
state_savegamemenu,     // State 3
state_loadgamemenu,     // State 4;
state_Exit,         // State 5;
state_other
};
state stateMmenu();
state statesettingmenu(string, string);
state stategamemenu();
state statesavegamemenu(string, string, string, ofstream&);
state stateloadgamemenu(string, string, string, ifstream&);
state stateExit();

int main()
{
state curr=state_other;
string filename= "PlayerOne.jak";
string fname="Player";
string lname="One";
ifstream inFS;
ofstream outFS;

while(curr != state_Exit)
{
    switch(curr)
    {
        case state_Mmenu:
        curr = stateMmenu();
        break;
        case state_settingmenu:
        curr = statesettingmenu(fname, lname);
        break;
        case state_gamemenu:
        curr = stategamemenu();
        break;
        case state_savegamemenu:
        curr = statesavegamemenu(fname, lname, filename, outFS);
        break;
        case state_loadgamemenu:
        curr = stateloadgamemenu(fname, lname, filename, inFS);
        break;
        default:
            cout << "Don't Tip the Vending Machine"<<endl;
            curr = state_Mmenu;
        break;
    }
}

return 0;
 }

state statesavegamemenu(string fname, string lname, string filename, 
ofstream outFS)
{
state next=state_savegamemenu;
int choice4=0;
cout<<" -Save Game Menu-----------------"<<endl;
cout<<"1. File Name - "<<filename<<endl;
cout<<"2. Save" <<endl;
cout<<"3. Game Menu" <<endl;
cout<<"----------------------------"<<endl;
    do
{
    cout << "Choice? "<< endl;
    cin >> choice4;
    cin.clear();
    cin.ignore(10000,'n');
}while(!cin.good());
switch(choice4)
{
    case 1:
    {
        cout<<"What would you like to save this file as? ";
        cin>>filename;
        cout<<endl;
        next = state_savegamemenu;
    }
    break;
    case 2:
    {
        outFS.open(filename.c_str());
        if(!outFS.is_open())
        {
            next = state_savegamemenu;
            break;
        }
        else
        {
            outFS<<fname<<endl;
            outFS<<lname<<endl;
        }
        outFS.close();
        next = state_savegamemenu;
    }
    break;
    case 3:
        next = state_gamemenu;
    break;
    default:
    cout << "Bad Input!"<<endl;
        next = state_savegamemenu;
    break;  
}
cout <<endl;
return next;
}
state stateloadgamemenu(string fname, string lname, string filename, 
ifstream inFS)
{
state next=state_loadgamemenu;
int choice5=0;
cout<<" -Save Game Menu-----------------"<<endl;
cout<<"1. File Name - "<<filename<<endl;
cout<<"2. Load" <<endl;
cout<<"3. Main Menu" <<endl;
cout<<"----------------------------"<<endl;
string filecontent;
    do
{
    cout << "Choice? "<< endl;
    cin >> choice5;
    cin.clear();
    cin.ignore(10000,'n');
}while(!cin.good());
switch(choice5)
{
    case 1:
    {
        cout<<"What file would you like to load? ";
        cin>>filename;
        cout<<endl;
        next = state_loadgamemenu;
    }
    break;
    case 2:
    {
        inFS.open(filename.c_str());
        if(!inFS.is_open())
        {
            next = state_savegamemenu;
            break;
        }
        else
        {
            while(!inFS.eof())
            {
                inFS >> filecontent;
                if(inFS.good())
                {
                    cout << filecontent << endl; 
                }
            }
        }
        inFS.close();
        next = state_loadgamemenu;
    }
    break;
    case 3:
        next = state_Mmenu;
    break;
    default:
    cout << "Bad Input!"<<endl;
        next = state_loadgamemenu;
    break;  
}
cout <<endl;
return next;
}

我遇到的错误是对StatesaveGameMenu((和StateloAdgamemenu((的不确定的引用。对于我的知识范围,这样的链接器错误与该程序无法找到有关函数的定义有关,但是我显然已经实施了它们,所以我对为什么会发生这种情况以及任何帮助我感到非常困惑将不胜感激。

在保存游戏和加载游戏中,您忘了这样做,因此与呼叫不匹配

 state statesavegamemenu(string fname, string lname, string filename, 
ofstream outFS)
{

to

 state statesavegamemenu(string fname, string lname, string filename, 
 ofstream& outFS)
 {  

与其他功能相同,但ifstream而不是ifstream&amp;