绘制线维纳皮

Drawing line WINAPI

本文关键字:绘制      更新时间:2023-10-16

我想通过单击并将光标从一个点移动到另一个点来画一条线,我刚刚复制了以下代码,任何我的 WindowProcedure 看起来像这样:

LRESULT CALLBACK WindowProc(HWND hwnd, UINT uMsg, WPARAM wParam, LPARAM lParam)
{   
    //PAINTSTRUCT ps;
    HDC hdc;
    bool draw = false;
    int x = 0, y=0;
    //InvalidateRect(hwnd, NULL, true);
    switch (uMsg)
    {
    case WM_LBUTTONDOWN:
            draw = true;
            x = LOWORD(lParam);
            y = HIWORD(lParam);
            return 0;
    case WM_LBUTTONUP:
        if (draw)
        {
            hdc = GetDC(hwnd);
            MoveToEx(hdc, x, y, NULL);
            LineTo(hdc, LOWORD(lParam), HIWORD(lParam));
            ReleaseDC(hwnd, hdc);
        }
        draw = FALSE;
        return 0;
    case WM_MOUSEMOVE:
        if (draw)
        {
            hdc = GetDC(hwnd);
            MoveToEx(hdc, x, y, NULL);
            LineTo(hdc, x = LOWORD(lParam), y = HIWORD(lParam));
            ReleaseDC(hwnd, hdc);
        }
        return 0;

    case WM_DESTROY:
        PostQuitMessage(0);
        return 0;
    }
    return DefWindowProc(hwnd, uMsg, wParam, lParam);
   }

但是当我点击什么也没发生时,就像一次只能处理一个案例一样,对吗?当我评论前两种情况时,它会画线,所以它进入切换,但这不是我想做的。 有什么建议吗?

LRESULT CALLBACK WindowProc(HWND hwnd, UINT uMsg, WPARAM wParam, LPARAM lParam)
{   
    //PAINTSTRUCT ps;
    HDC hdc;
    static bool draw = false;  // ←static
    static int x = 0, y=0;     // ←

怎么样?