"bubble sort algorithm"小错误

我被给予了：

"编写一个实现整数数组的气泡排序的函数。该函数的原型如下：void sort（int data []，int count）;

编写一个提示文件名的程序，打开该文件并将数字从文件中读取到数组。然后，您的程序应调用您的排序例程，然后打印结果数组。"

我完成了它，它的工作正常，直到我被告知数字已经按秩序的情况下也必须尽早停止。您将在下面的void函数中看到这种尝试。我没有遇到任何错误；该程序编译，执行并关闭良好。现在的问题是添加了布尔变量，它不再分类数字。它将以与文本文件相同的顺序打印出它们。我通过调试器进行了运行，并注意到" II"变量并没有像应该（...; ...; ii ）那样增加1个通行证，而是保持0。任何想法？<<

" integers.txt"文件中的（随机）数字：12 42 5 67 41 9 19 93 10 124 21

void sort(int data[], int count);
int main()
{
    const int MAX_SIZE = 128;
    char fileName[MAX_SIZE];
    int data[MAX_SIZE];
    int count = 0;
    cout << "Enter a file name: "; //integers.txt
    cin.clear();
    cin.ignore(cin.rdbuf()->in_avail());
    cin.getline(fileName, sizeof(fileName));
    ifstream input(fileName); //opens the file and reads the first line
    if (input.is_open())
    {
        while (!input.eof() && count <= MAX_SIZE) //adds data to the array until the end of the file is reached
        {
            input >> data[count];
            count += 1;
        }
    input.close();
    }
    else
    {
        cout << "nThe file failed to open, try again.n";
    }
    sort(data, count); //calls the bubble sort function
    return 0;
}
void sort(int data[], int count)
{
    int temp = 0;
    int pass = 0;
    bool sorted = false;
    for (int pass = 0; pass <= count; pass += 1) //counts the number of passes
    {
        for (int ii = 0; (ii <= (count - pass - 1)) && (sorted = false) ; ii++) //sorts the integers from least to greatest
        {                                                                       //also 'supposed to' stop early if already sorted
            if (data[ii] > data[ii + 1])
            {
                sorted = false;
                temp = data[ii];
                data[ii] = data[ii + 1];
                data[ii + 1] = temp;
            }
        } 
    }
    cout << "nSorted integers: ";
    for (int jj = 1; jj <= count; jj += 1) //prints the sorted integers
    {
        cout << data[jj] << " ";
    }
    cout << "nn";
}