调用'class'没有匹配函数

No matching function for call to 'class'

本文关键字:函数 class 调用      更新时间:2023-10-16

我正在努力学习和理解多重继承。

我有一个"蹲着"的班,是一个"被遗弃"的班的孩子

为什么我得到错误消息没有匹配的函数调用放弃::放弃()

swatcher.cpp|9|错误:调用"放弃::放弃()"|时没有匹配的函数

我在这个网站上看了很多与这个话题相关的类似帖子。他们说我必须用正确的论据声明一个被放弃的对象,但我不想使用被放弃的任何函数,我现在只想把它联系起来。

我认为这与我的构造函数有关,但我不知道问题出在哪里。

抱歉代码太多了,但我想不出更好的方法

这是我的深蹲.cpp/h

#ifndef SQUAT_H
#define SQUAT_H
#include<abandoned.h>
#include<building.h>
class Squat:public Buildings, public Abandoned
{
private:
bool isempty;
public:
Squat(bool);
virtual void display();
virtual void isoccupied(bool);

};

#endif // SQUAT_H

和.cpp

#include<iostream>
#include<squat.h>
#include<building.h>
#include<apartment.h>
#include<abandoned.h>

Squat::Squat(bool isitempty):isempty(isitempty){}
void Squat::isoccupied(bool isitempty)
{
if(isitempty=1)
{
isempty=1;
cout<<"The abandoned building is empty"<<endl;
}
else cout<<"The abandoned building is full of dirty squatters"<<endl;
}

我的理解是当我说过;

class Squat:public Buildings, public Abandoned

这已经将类"链接"在一起

下面是我放弃的.cpp/h

#ifndef ABANDONED_H
#include<vector>
#include<building.h>
#define ABANDONED_H

class Abandoned:public Buildings
{
private:
int length;
std::vector<int> status;
int sum;
public:
Abandoned(int m_size, int asum);
Abandoned(bool);
virtual void getstatus(int);
virtual void display();
virtual void demolish(int);
virtual void rebuild(int);
//virtual void demolish(int);

};



#endif // ABANDONED_H

和我的.cpp

#include<iostream>
#include<string>
#include<vector>
#include<apartment.h>
#include<building.h>
#include<abandoned.h>
#include<algorithm>
#include<numeric>
using namespace std;
Abandoned::Abandoned(int m_size, int asum): length(m_size), status(m_size, 0), sum(asum)
{}

void Abandoned::getstatus(int m_size)
{
status.push_back(length);
};
void Abandoned::display()
{
Buildings::display();
cout << " length of status is: "<<status.size()<<endl;
}
void Abandoned::demolish(int asum)
{
if(asum<3)
{
cout<<"The building is below the safety standards and should be demolished"<<endl;
}else{
cout<<"The building meets the safety standards and can be rebuilt"<<endl;}
}
void Abandoned::rebuild(int asum)
{
if(asum>3)
{
cout<<"The building is above the safety standards and should be rebuilt"<<endl;
}else{
cout<<"The building should be demolished"<<endl;}
}

Abandoned没有无arg构造函数。这意味着派生类的任何构造函数都必须从Abandoned:中选择一个要调用的构造函数

Squat::Squat(bool isitempty): Abandoned(...), isempty(isitempty){}