显示将来自用户输入的数组的最小值和最大值

Show min and max values of array that will come from user input

本文关键字：数组 最小值 最大值 输入 将来 用户 显示      更新时间：2023-10-16

我正在制作一个简单的程序，它将要求输入，将其放入数组(数字[i])中并将其转换为三个不同的单位。将其转换为不同的单位后，我必须能够显示用户给出的最低和最高数字。

我正在使用 do while 循环从用户那里获取输入，在do while loop之后，我放了一个for loop，它将根据 number[i] 数组内的输入计算最小和最大数字。但是输入 2 个输入后，程序只向我显示最高数字，最低数字显示我0.

这是它的样子。

do{
clrscr();
cout<<"Enter a number:";
cin>>number[i];
cout<<"nPlease choose a unit";
cout<<"n<A> meter";
cout<<"n<B> centimeter";
cout<<"n<C> inch";
cout<<"n<D> feet";
cout<<"nPlease enter your chosen unit: ";
cin>>unit;
switch(unit)
{
case 'a':
case 'A':
i=0;
m = number[i] * 1;
cm = 1000 * m;
in =  m / 0.0254;
ft =  m/0.3048;
cout<<"nYou have chosen meter for unit";
cout<<"nYou have entered "<<number[i]<<" meters";
cout<<"n"<<m<<" meters is equal ton"<<cm<<" centimeters";
cout<<"n"<<in<<" inches";
cout<<"n"<<ft<<" feet";
cout<<"nnDo you want to input another value? y/n:";
cin>>y;
if(y=='y')
{
x=1;
}
else if(y=='n')
{
x=0;
}
break;
case 'b':
case 'B':
cm = number[i] * 1;
m = cm /1000;
in = cm * 0.393701;
ft = cm * 0.0328084;
cout<<"nYou have chosen centimeter for unit";
cout<<"nYou have entered "<<number[i]<<" centimeters";
cout<<"n"<<cm<<" centimeters is equal ton"<<m<<" meters";
cout<<"n"<<in<<" inches";
cout<<"n"<<ft<<" feet";
cout<<"nnDo you want to input another value? y/n:";
cin>>y;
if(y=='y')
{
x=1;
}
else if(y=='n')
{
x=0;
break;
}
break;
case 'c':
case 'C':
in = number[i] * 1;
m = in * 0.0254;
cm = in * 2.54;
ft = in * 0.0833333;
cout<<"nYou have chosen inches for unit";
cout<<"nYou have entered "<<number[i]<<" inches";
cout<<"n"<<in<<" inches is equal ton"<<m<<" meters";
cout<<"n"<<cm<<" centimeters";
cout<<"n"<<ft<<" feet";
cout<<"nnDo you want to input another value? y/n:";
cin>>y;
if(y=='y')
{
x=1;
}
else if(y=='n')
{
x=0;
}
break;
case 'd':
case 'D':
ft = number[i] * 1;
m = ft*0.3048;
in = ft*12;
cm = ft * 30.48;
cout<<"nYou have chosen feet for unit";
cout<<"nYou have entered "<<number[i]<<" feet";
cout<<"n"<<ft<<" feet is equal ton"<<m<<" meters";
cout<<"n"<<cm<<" centimeters";
cout<<"n"<<in<<" inches";
cout<<"nnDo you want to input another value? y/n:";
cin>>y;
if(y=='y')
{
x=1;
}
else if(y=='n')
{
x=0;
}
break;
default:
cout<<"nYou have entered an invalid choice!";
x=1;
break;
}
}while(x==1);
for(i=0; i<sizeof(number)/sizeof(*number);i++)
{
if(mn>number[i])
{
mn=number[i];
}
else if (mx<number[i])
mx= number[i];
}
cout<<"nHighest number is : "<<mx;
cout<<"nLowest number is: "<<mn;

如果您获得最低数字输出的最高数字，则第二个cout语句中存在错误，则您继续具有mx的输出

当前您使用mx作为最低数字

cout<<"nLowest number is: "<<mx;

固定

cout<<"nLowest number is: "<<mn;

使用minmax：

const auto result = minmax(cbegin(number), cend(number));
cout << "nHighest number is : " << result.first << "nLowest number is: " result.second << endl;

您正在将i与number[i]进行比较，而是将其与number的大小进行比较。

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