坚持认为学校的C 日历代码

Stuck with figuring C++ calendar code for school

本文关键字:日历 代码 为学校 坚持      更新时间:2023-10-16

我是为了将日历作为学校项目制作代码,而我几乎完成了。但是,运行申请时,本月的天数将继续,并且在最后一天的数量不会停止。我相信这与给出当月日子(int numdaysmonth)的部分有关。我需要将其保留为一个数组,因为这是标题的分开。

这是主要的:

#include <cstdlib>
#include <iostream>
#include "LeapYear.h"
#include "calendar.h"
using namespace std;
int main(int argc, char *argv[])
{
functions();
system("PAUSE");
return EXIT_SUCCESS;
}

这是创建日历的地方(链接到其他文件的单独文件)...

#include <iostream>
#include <iomanip>
#include "LeapYear.h"
#include"calendar.h"
using namespace std;

/**********************************************************************
* This function will call all the functions necessary to make a calendar
* for any given month and year.
***********************************************************************/
int functions()
{
int numDays;
int offset;
int month;
int year;
month = getMonth(month);
year = getYear(year);
offset = computeOffset(year, month);
display(year, month, offset);
return 0;
}
/***********************************************************************
* Gets the month number.
**********************************************************************/
int getMonth(int month)
{
cout << "Enter a month number: ";
cin >> month;
while ( month < 1 || month > 12)
{
cout << "Month must be between 1 and 12.n"
<< "Enter a month number: ";
cin >> month;
}
return month;
}
/***********************************************************************
* Gets the year.
**********************************************************************/
int getYear(int year)
{
cout << "Enter year: ";
cin >> year;
while ( year < 1753)
{
cout << "Year must be 1753 or later.n"
<< "Enter year: ";
cin >> year;
}
return year;
}
/***********************************************************************
* Computes the offset.
**********************************************************************/
int computeOffset(int year, int month)
{
int offset = 0;
int count = year - 1753;
for ( int iYear = 0; iYear < count; iYear++)
{
offset = ( offset + 365 + isLeapYear(year)) % 7;
}
for ( int iMonth = 1; iMonth < month; iMonth++)
{
offset = ( offset + numDaysMonth(year, iMonth)) % 7;
}
return offset;
}

/***********************************************************************
* Computes the number of days in the given year.
**********************************************************************/
int numDaysYear(int year)
{
int daysYear = 365 + isLeapYear(year);
return daysYear;
}
/***********************************************************************
* Gets the number of days in the given month.
**********************************************************************/
int numDaysMonth(int year, int month)
{
int daysMonth[13];
daysMonth[0] = 31;
daysMonth[1] = 29;
daysMonth[2] = 28;
daysMonth[3] = 31;
daysMonth[4] = 30;
daysMonth[5] = 31;
daysMonth[6] = 30;
daysMonth[7] = 31;
daysMonth[8] = 31;
daysMonth[9] = 30;
daysMonth[10] = 31;
daysMonth[11] = 30;
daysMonth[12] = 31;
if ( month == 1)
daysMonth[0];
else if ( month == 2)
{
if (isLeapYear(year) == true)
daysMonth[1];
else
daysMonth[2];
}
else if ( month == 3)
daysMonth[3];
else if ( month == 4)
daysMonth[4];
else if ( month == 5)
daysMonth[5];
else if ( month == 6)
daysMonth[6];
else if ( month == 7)
daysMonth[7];
else if ( month == 8)
daysMonth[8];
else if ( month == 9)
daysMonth[9];
else if ( month == 10)
daysMonth[10];
else if ( month == 11)
daysMonth[11];
else if ( month == 12)
daysMonth[12];
}

/**********************************************************************
* Displays the calender table.
**********************************************************************/
void display(int year, int month, int offset)
{
int dayOfWeek;
int day;
cout << endl;
if ( month == 1)
cout << "January";
else if ( month == 2)
cout << "February";
else if ( month == 3)
cout << "March";
else if ( month == 4)
cout << "April";
else if ( month == 5)
cout << "May";
else if ( month == 6)
cout << "June";
else if ( month == 7)
cout << "July";
else if ( month == 8)
cout << "August";
else if ( month == 9)
cout << "September";
else if ( month == 10)
cout << "October";
else if ( month == 11)
cout << "November";
else if ( month == 12)
cout << "December";

cout << ", " << year << "n";
// Display month header
cout << " Su Mo Tu We Th Fr San";
// Gets the correct offset width and end the line on the right
//day of the week
if (offset == 0)
{
day = 2;
cout << setw(6);
}
else if (offset == 1)
{
day = 3;
cout << setw(10);
}
else if (offset == 2)
{
day = 4;
cout << setw(14);
}
else if (offset == 3)
{
day = 5;
cout << setw(18);
}
else if (offset == 4)
{
day = 6;
cout << setw(22);
}
else if (offset == 5)
{
day = 7;
cout << setw(26);
}
else if (offset == 6)
{
day = 1;
cout << setw(2);
}
else
cout << "Error offset must be >= 0 and <=6n";
// The loop for displaying the days and ending the line in the right place
for ( dayOfWeek = 1; dayOfWeek <= numDaysMonth(year, month); dayOfWeek++ )
{
cout << " " << setw(2) << dayOfWeek;
++day;
if (day == 8)
{
cout << "n";
day = 1;
}
}
if ( day >= 2 && day <= 7)
cout << "n";
}

然后,我有一个单独的文件链接到该文件:

#include <iostream>
#include <iomanip>
#include "LeapYear.h"
#include"calendar.h"
using namespace std;
/***********************************************************************
* Determines if given year is a leap year.
**********************************************************************/
bool isLeapYear(int year)
{
if ( year % 4 == 0 && year % 100 != 0 || year % 400 == 0)
return true;
else
return false;
}

然后是第一个标头文件...

bool isLeapYear(int year);

和第二个标头文件...

int getMonth(int month);
int getYear(int year);
int computeOffset(int year, int month);
int numDaysYear(int year);
int numDaysMonth(int year, int month);
bool isLeapYear(int year);
void display(int year, int month, int offset);

您错过了numDaysMonth()中的所有返回语句。

如果您使用编译器的额外警告来编译代码,那么您肯定会"从功能中返回而没有价值"的诊断类型。

在这里:

for (dayOfWeek = 1; dayOfWeek <= numDaysMonth(year, month); dayOfWeek++)

您取决于numDaysMonth()的返回值以停止日历的显示。如果您检查该功能,它不会返回您的意图,因为您没有明确指定返回。

由于您需要使用数组 - 一种可以重构的方法是:

int numDaysMonth(int year, int month)
{
  const int LEAP_FEBRUARY = 13;
  int daysMonth[13];
  daysMonth[0] = 31;
  daysMonth[1] = 28;
  daysMonth[2] = 31;
  daysMonth[3] = 30;
  daysMonth[4] = 31;
  daysMonth[5] = 30;
  daysMonth[6] = 31;
  daysMonth[7] = 31;
  daysMonth[8] = 30;
  daysMonth[9] = 31;
  daysMonth[10] = 30;
  daysMonth[11] = 31;
  daysMonth[12] = 31;
  daysMonth[LEAP_FEBRUARY] = 29;
  if (month == 2) {
    if (isLeapYear(year)) {
      return daysMonth[LEAP_FEBRUARY];
    }
    else {
      return daysMonth[1];
    }
  } 
  return daysMonth[month - 1];
}