我的获取函数不起作用

My get function isn't working

本文关键字：不起作用 函数 获取 我的      更新时间：2023-10-16
class Cat {
public:
    string getname() const;
    void setname(string name);
private:
    string name;
    // constructor
    Cat(string name) {
        this->name = name;
        cout<<"Cat's name is "<< name << endl;
    }
};
int main Cat::getname() {
    string name ="Assignment 09";
    cout << name << endl;
    Dog fido("Fido");
    Cat spot("Spot");
    cout <<"From main, the Dog's name is "<< fido.name << endl;
    cout <<"From main, the Cat's name is "<< spot.name << endl;
    cout <<"Hit any key to continue"<< endl;
    system("pause");
    return name;
}

要从对象中获取名称，需要使用getname方法：

// Note the removal of Cat::getname()
int main (void)
{
    string name ="Assignment 09";
    cout << name << endl;
    Dog fido("Fido");
    Cat spot("Spot");
    // Note the changes here:  fido.getname()
    cout <<"From main, the Dog's name is "<< fido.getname() << endl;
    // Similarly:  spot.getname()
    cout <<"From main, the Cat's name is "<< spot.getname() << endl;
    cout <<"Hit any key to continue"<< endl;
    system("pause");
    return name;
}

fido.getname()是一个假设，因为您在问题中没有提供Dog的类定义。

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