C++ 如何执行添加新值并可以删除现有值的循环

感谢您阅读这个问题。

基本上，我正在尝试编写可以实现以下内容的代码：

用户将看到如下所示的详细信息列表

终端视图：

Please select the department you want to add participant: 
1. Admin 
2. HR 
3. Normal 
4. Back to Main Menu 
Selection: 3
normal's Department
 UserID: 85 [ Name: Andrew, Department:  normal ]
 UserID: 86 [ Name: Jacky, Department:  normal ]
 UserID: 90 [ Name: Baoky, Department:  normal ]
Current Selected Participant : 
Usage: 
Type exit to return to main menu
Type remove userid to remove participant
Type add userid to add participant
Selection: 

问题是：我希望能够让用户添加任意数量的参与者，直到他决定"退出"到主菜单，但是我如何将其存储在字符串参与者中。

如何检测用户输入是"删除用户 ID"或"添加用户 ID"，然后获取用户 ID

例如添加 86然后他加上 90

然后他决定删除 90

字符串如何跟上它

下面是我的代码：

do
{
cout << "Current Selected Participant : " << participant << endl; 
cout << "" << endl;
do
{
if(counter>0)
{
//so it wont print twice
cout << "Usage: " << endl; 
cout << "Type exit to return to main menu" << endl;
cout << "Type remove userid to remove participant" << endl;
cout << "Type add userid to add participant" << endl;
cout << "" << endl;
cout << "Selection: ";
}
getline(cin,buffer);
counter++;
}while(buffer=="");


if(buffer.find("remove"))
{
str2 = "remove ";
buffer.replace(buffer.find(str2),str2.length(),"");
if(participant.find(buffer))
{
//see if buffer is in participant list
buffer = buffer + ",";
participant.replace(participant.find(buffer),buffer.length(),"");
}
else
{
cout << "There no participant " << buffer << " in the list " << endl;
}
}//buffer find remove keyword

if(buffer=="exit")
{
done=true;
}
else
{
sendToServer = "check_account#"+buffer;
write (clientFd, sendToServer.c_str(), strlen (sendToServer.c_str()) + 1);
//see if server return found or not found
readFromServer = readServer (clientFd);
if(readFromServer=="found")
{
//add to participant list
participant += buffer;
participant += ",";
}
}//end if not exit
}while(done!=true);

一些用户建议我存储在字符串集中，如何存储在字符串集中，以及如何使终端能够识别选择中的"删除"和"添加"等关键字

然后获取用空格分隔的用户 ID。

接下来是如何删除我是否存储在字符串集中以及如何推送新值。