如何在多个 (.txt） 文件中输出内容

How to output content in multiple (.txt) files

本文关键字：文件 输出 txt      更新时间：2023-10-16

我创建了一个程序，该程序可以从文件中获取整数作为输入，并生成从1到从文件中读取的整数的乘法表。例如，如果程序从文件中读取 (3(，它将输出：

1*1 = 1
1*2 = 2
... up to
1*10 = 10
and then 
2*1 = 1 
.....
2*10 = 10
and so on up to three suppose that the number read from the file is 3
3*1 = 1
....
3*10 = 30

现在，我正在尝试在不同的(.txt(文件中输出每个乘法表，例如table1.txt将包含1*1 = 1 .... up to 1*10 = 10，table2.txt将包含2*1 = 2 .... up to 2*10 = 10和表3.txt的相同过程。

我只能创建一个仅包含第一个乘法表的文件，并且我不知道如何在不同的文件中显示其余的表。

我非常感谢解决这个问题的任何帮助或见解。谢谢！

这是我所拥有的：

#include <iostream>
#include <fstream>
using namespace std;
int main ()
{
    int num, a, b;
    fstream inputStream;
    ofstream outputStream;
    inputStream.open("input.txt"); //let's say input.txt holds the number 3
    while (inputStream >> num)
    outputStream.open("table.txt");
    for (a = 1; a <= num; a++) 
    {
        for (b = 1; b <= 10; b++)
        {
            outputStream << a << " X "
                   << b << " = "
                   << a*b << endl;
        }
        inputStream.close();
        outputStream.close();
    }                  
    return 0;
}

#include <iostream>
#include <string>
#include <fstream>
int main(void) {
    const int Count = 10;              //Count of files
    std::string name = "example_";     //base pattern of file name
    std::ofstream outfstr[Count];      //creating array of 10 output file streams
    for(int i = 0; i < Count; ++i) {   //open all file streams 
        outfstr[i].open(name + char('0' + i) + ".txt");
    }
    for(int i = 0; i < Count; ++i) { // write value of i to i-th stream
         outfstr[i] << "Some rezult " << i;
    }
    return 0;
}
相关文章：