从c++程序中运行一些程序的多个副本

我需要做的是从主程序中使用不同的命令行参数运行example.exe（也是我的程序）的6个副本。这些副本应在的同时工作。我使用的代码是这样的：

    const int NumberOfProcesses= 6;    
    STARTUPINFO si[NumberOfProcesses];
    PROCESS_INFORMATION pi[NumberOfProcesses];

    srand((unsigned)time(NULL));
    for(int i=0;i<NumberOfProcesses;i++)
    {
    char fname[MAX_PATH];
    strncpy(fname,""",1);
    fname[1] = '';
    strcat(fname,"d:\test\example.exe");
    strcat(fname,""");
    int id = i;
    strcat(fname," ");
    strcat(fname,(std::to_string(id)).c_str());
    int count = (rand()%1000) + 1;
    strcat(fname," ");
    strcat(fname,(std::to_string(count)).c_str());
    int lb = 13;
    strcat(fname," ");
    strcat(fname,(std::to_string(lb)).c_str());
    int ub = 666;
    strcat(fname," ");
    strcat(fname,(std::to_string(ub)).c_str());
    printf(fname);    
    cout<<"n";
    //Here in fname I have correct command, that runs properly
        bool t = false;
        t=CreateProcess( NULL,   // No module name (use command line)
                (LPSTR)fname,        // Command line CharToLPWSTR(fname2)
                NULL,           // Process handle not inheritable
                NULL,           // Thread handle not inheritable
                FALSE,          // Set handle inheritance to FALSE
                0,              // No creation flags
                NULL,           // Use parent's environment block
                NULL,           // Use parent's starting directory 
                &si[i],            // Pointer to STARTUPINFO structure
                &pi[i] );           // Pointer to PROCESS_INFORMATION structure
    }

因此，如果NumberOfProcesses==0，它将从fname运行"d:\test\example.exe"1 2 3 4。但如果NumberOfProcesses==6（或其他什么），零迭代将正确完成，但其他迭代将返回false。有时第4次迭代运行正常。

我认为这是因为当零迭代运行"d:\test\example.exe"1 2 3 4时，example.exe正忙，无法再运行一次。所以我把代码改成了这个：

 bool t = false;
        getchar();
        for(int i=0;i<5;i++)
        {
        t=CreateProcess( NULL,   // No module name (use command line)
                (LPSTR)fname,        // Command line CharToLPWSTR(fname2)
                NULL,           // Process handle not inheritable
                NULL,           // Thread handle not inheritable
                FALSE,          // Set handle inheritance to FALSE
                0,              // No creation flags
                NULL,           // Use parent's environment block
                NULL,           // Use parent's starting directory 
                &si[i],            // Pointer to STARTUPINFO structure
                &pi[i] );           // Pointer to PROCESS_INFORMATION structure
        if(t) break;
        }

因此，我在启动example.exe之间出现了一些延迟，这对有所帮助。所有6个副本都开始和结束，但它们不是并行运行的（我有example.exe的输出）。但这不是我想要的程序工作方式。

我该如何避免这个问题？谢谢

UPD根据Werner Henze的回答，我刚刚在循环中添加了几行（到初始化STURTUPINO）

const int NumberOfProcesses= 6;    
STARTUPINFO si[NumberOfProcesses];
PROCESS_INFORMATION pi[NumberOfProcesses];
for(int i=0;i<NumberOfProcesses;i++)
{
///Next two lines is important
 ZeroMemory( &si[i], sizeof(si[i]) );
   si[i].cb = sizeof(si);
/*Some actions*/
t=CreateProcess( NULL,   // No module name (use command line)
                    (LPSTR)fname,        // Command line CharToLPWSTR(fname2)
                    NULL,           // Process handle not inheritable
                    NULL,           // Thread handle not inheritable
                    FALSE,          // Set handle inheritance to FALSE
                    0,              // No creation flags
                    NULL,           // Use parent's environment block
                    NULL,           // Use parent's starting directory 
                    &si[i],            // Pointer to STARTUPINFO structure
                    &pi[i] );           // Pointer to PROCESS_INFORMATION structure
}

现在一切都很顺利。再次感谢。