函数指针，错误无法将参数 1 转换为常量字符

我迷失了这段代码，我需要做什么

Couple *pcouple1 = new Couple(mary, *pjohn);
Couple couple2(*pjane, mark);

上班？我在夫妇（玛丽和夫妇2（*pjane与以下信息：

*

错误 C2664："耦合：：耦合（常量耦合 &）"：无法将参数 1 从"人"转换为"常量字符 *"

*智能感知：构造函数"Couple：：Couple"的实例与参数列表匹配 参数类型为：（人，人）

代码是：

班级情侣和人

class Person {
char* name;    
public:
friend class Couple;
friend ostream& operator<<(ostream& str, const Person& os)
{
    str << os.name;
    return str;
};
Person(const char* n)
{
    name = (char*)n;
    cout << "char constructor   " << name << endl;
};
Person(const Person& os)
{
    name = os.name;
    cout << "Person constructor " << name << endl;
};
Person& operator=(const Person& os)
{
    this->name = os.name;
    return *this;   
};
~Person()
{
    free(name);          
    cout << "Class Person Destructor" << endl;
};
char* getName(){
    return name;
    };
};
class Couple {
Person *wife, *husband;
public:
friend ostream& operator<<(ostream& str, const Couple& p)
{
    str << "He " << *p.husband << " She " << *p.wife;
};
Couple::Couple(const char* m, const char* z)
{
    husband = new Person(m);
    wife = new Person(z);
    cout << "Couple1: " << endl;
};
Couple::Couple(const Couple& other)
{
    husband = new Person(*other.husband);
    wife = new Person(*other.wife);
    cout << "Couple2: " << endl;
}
Couple& operator=(const Couple& other)
{
    this->husband = new Person(*other.husband);
    this->wife = new Person(*other.wife);
    return *this;
};

~Couple()
{
    free(husband->name);
    free(husband);
    free(wife->name);
    free(wife);
    cout << "Class Couple Destructor" << endl;
};
};

主要功能：

int main(void) {
Person *pjohn = new Person("John"),
       *pjane = new Person("Jane");
Person mary("Mary"), mark("Mark");
Couple *pcouple1 = new Couple(mary, *pjohn);
Couple couple2(*pjane, mark);
    delete pjohn;
    delete pjane;
    cout << *pcouple1 << endl;
    cout << couple2 << endl;
    couple2 = *pcouple1;
    delete pcouple1;
    cout << couple2 << endl;

return 0;
}

有人可以向我推荐一个好的资源/站点/书籍/练习，以更好地理解与此练习类似的函数指针，提前感谢我还在学习。