再次运行程序并将结果存储在数组中

Running program again and storing result in an array

本文关键字：存储数组结果运行程序更新时间：2023-10-16

这是我在这里用于匹配子字符串的程序。我想更改程序中输入和输出的工作方式。

问题定义：

系统会提示用户输入多少个字符串（N）
N 个字符串将在单独的行上输入
对于每个字符串，
如果以"hackerrank"开头，则打印 1
如果以"hackerrank"结尾，则打印 2
如果以"hackerrank"开头和结尾，则打印 0
如果以上都不是，则打印 -1

例：

输入：

4
i love hackerrank
hackerrank is an awesome place for programmers
hackerrank
i think hackerrank is a great place to hangout

Output:
2
1
0
-1

这是我的实际代码。

int main()
{
    vector<string> token_store;
    string s,token;

    getline(cin,s);
    std::istringstream iss(s);

    while(iss>>token)
        token_store.push_back(token);   //splitting strings into tokens

    int len=token_store.size();        //storing size of vector
    if(token_store[0]=="hack" && token_store[len-1]=="hack")
       cout<<"first and last same";     //if first and last word of input string is hack
    else if(token_store[0]=="hack")
       cout<<"first matches";                                    //if first word of input string is hack
    else if(token_store[len-1]=="hack")
       cout<<"last matches";                                 //if last word of input string is hack
}

以下代码将读取输入并检查字符串"hackerrank"

#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main()
{
    vector<string> token_store;
    int amount;
    string s;
    cin >> amount;
    cin.ignore();
    for(int i = 0; i < amount; i++){
        getline(cin, s);
    token_store.push_back(s);
    }
    string match = "hackerrank";
for(int i = 0; i < amount; i++){
    bool starts = false;
    bool ends = false;
    string str = token_store[i];
    if(str.length() < match.length()){
        std::cout << -1 << "n";
        continue;
    }
    starts = str.substr(0, match.length()) == match; // Check if string starts with match
    ends = str.substr(str.length()-match.length()) == match; // Check if string ends with match
    if(starts && ends)
        std::cout << 0 << "n";
    else if(starts)
        std::cout << 1 << "n";
    else if(ends)
        std::cout << 2 << "n";
    else
        std::cout << -1 << "n";
    }
    return 0;
}