注意:(getline不是问题所在）C++getline(）停止在用户定义的函数中工作，但在主函数中工作

注意：已解决，问题不是getline()，而是用数组填充不正确！

在发布自己的问题之前，我已经查了几个问题，但我找不到问题的答案。这是我发布的第一个问题，但在发布自己的问题之前，我确实做了一些研究，并尝试了其他问题的其他解决方案。所以我不完全确定这不是重复的。我很抱歉！感谢您的提前理解！

我正在尝试使用getline()(c++)来获取用户输入。它在我的main中运行良好，但在我的用户定义函数中不起作用。我认为这可能与缓冲区有关，所以我使用了cin.ignore()，如中所建议的那样

C++getline方法不工作

我检查了一下：

getline如何与cin合作？

以确保我正确理解getline()。然而，我的程序仍然不能正常工作。

我的程序将英文文本作为用户输入(控制台输入)的字符串，并将其转换为莫尔斯电码，并将结果作为字符串输出(控制台输出)。

基本上我的问题是：

getline在我的主函数中既适用于字符串，也适用于空格为"This"answers"This Code"的字符串。

然而，在我的用户定义函数中，它只适用于没有空格的字符串，例如："This"。

谢谢你的帮助！下面的代码片段！

#include <iostream>;
#include <stdio.h>;
#include <ctype.h>;
using namespace std;

string textToMorse(const string alphabet, const string morseAlphabet[]);
int main()
{
const string alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789.,?";
const string morseAlphabet[39] = {".-","-...","-.-.","-..",".","..-.","--.","....","
..",".---","-.-",".-..","--","-.","---",".--.",
"--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--..","-----",".----","..---",
"...--","....-",".....",
"-....","--...","---..","----.",".-.-.-","--..--","..--.."};
int userSelection;
string resultString;

cout << "TEXT TO MORSE CODE or MORSE CODE TO TEXT program" << endl << endl;
cout << "Please select an option by typing the integer shown: " << endl << endl;
cout << "Type(Selects option) 1 to decode Morse code to English text" << endl;
cout << "Type(Selects option) 2 to encode English text to Morse code" << endl;
cout << "Type(Select option) any other integer that is NOT 1 or 2 to QUIT" << endl << endl;
cin >> userSelection;
while(userSelection == 1 || userSelection == 2)
{
if(userSelection == 1)
{
resultString = textToMorse(alphabet, morseAlphabet); // function where I use 
// getline() but does not work
cout << endl << "This is the Morse code decoded to English text: " << endl << endl;
cout << resultString << endl << endl << endl << endl;
}
}
return 0;
}
// does not work
string textToMorse(const string alphabet, const string morseAlphabet[])
{
string userInput;
cout << endl << "Enter English text to encode to Morse code,
with only a space between words: " << endl << endl;
cin.ignore();
getline(cin,userInput); //code works with strings without spaces, 
//but breaks with others. ex: "This" works as input
//but "This code" breaks and the console seems to freeze
// then crashes out
cin.clear();
// rest of code, but program breaks before this.
string encodedEnglishText = "";
for(int i = 0; i < userInput.length(); i++)
{
userInput[i] = toupper(userInput[i]);
}
for(int i = 0; i < userInput.length(); i++)
{
encodedEnglishText += morseAlphabet[alphabet.find(userInput[i])];
encodedEnglishText += " "; // extra spacing added for output clarity
if(userInput[i] == ' ')
{
encodedEnglishText += "  "; // extra spacing added for output clarity
}
}
return encodedEnglishText;
}

但是，如果我编辑代码，从main中获取输入并将其作为参数传入，它就可以工作了。

#include <iostream>;
#include <stdio.h>;
#include <ctype.h>;
using namespace std;

string textToMorse(const string alphabet, const string morseAlphabet[], string userInput);
int main()
{
const string alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789.,?";
const string morseAlphabet[39] = {".-","-...","-.-.","-..",".","..-.","--.","....","
..",".---","-.-",".-..","--","-.","---",".--.",
"--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--..","-----",".----","..---",
"...--","....-",".....",
"-....","--...","---..","----.",".-.-.-","--..--","..--.."};
int userSelection;
string resultString;

cout << "TEXT TO MORSE CODE or MORSE CODE TO TEXT program" << endl << endl;
cout << "Please select an option by typing the integer shown: " << endl << endl;
cout << "Type(Selects option) 1 to decode Morse code to English text" << endl;
cout << "Type(Selects option) 2 to encode English text to Morse code" << endl;
cout << "Type(Select option) any other integer that is NOT 1 or 2 to QUIT" << endl << endl;
cin >> userSelection;
while(userSelection == 1 || userSelection == 2)
{
if(userSelection == 1)
{
string userInput;
cout << endl << "Enter English text to encode to Morse code,
with only a space between words: " << endl << endl;
cin.ignore();
getline(cin,userInput); //code works with both "This" and "This code"
cin.clear();
resultString = textToMorse(alphabet, morseAlphabet, userInput); //function modified 
     //to take one more
     //parameter
cout << endl << "This is the Morse code decoded to English text: " << endl << endl;
cout << resultString << endl << endl << endl << endl;
}
}
return 0;
}
string textToMorse(const string alphabet, const string morseAlphabet[], string userInput)
{
//code, but program works.
string encodedEnglishText = "";
for(int i = 0; i < userInput.length(); i++)
{
userInput[i] = toupper(userInput[i]);
}
for(int i = 0; i < userInput.length(); i++)
{
encodedEnglishText += morseAlphabet[alphabet.find(userInput[i])];
encodedEnglishText += " "; // extra spacing added for output clarity
if(userInput[i] == ' ')
{
encodedEnglishText += "  "; // extra spacing added for output clarity
}
}
return encodedEnglishText;
}

我没有包括所有的代码，只是我觉得与问题相关的部分。

我的意思是：

getline成功接受输入。当在main函数中使用时，getline成功地将诸如"this"answers"this code"之类的字符串分配给变量userInput。

当在我的用户定义函数中使用时，它只成功地分配了不带空格的字符串，比如"this"。在该函数中，由于某种原因，当我输入像"this code"这样的字符串或中间有空格的任何字符串时，它都不起作用。

注意：程序还没有完成，因为我计划添加其他方法来完成相反的操作(如代码额外的用户选项，但这些选项尚未实现或定义，代码仍在运行和编译以解决我面临的问题。