将字符串解析为结构变量

Parsing String into struct variables

本文关键字：结构变量字符串更新时间：2023-10-16

>我试图将字符串解析为具有不同变量的结构向量。这就是我目前所拥有的，但它似乎不起作用。

struct client
{
    string PhoneNumber;
    string FirstName;
    string LastName;
    string Age;
};
int main()
{
    string data = getClientDatabase();
    vector <client> clients;
    parse_string(data, clients);
    return 0;
}
string getClientDatabase()
{
    return
        "(844)615-4504 Sofia Ross 57 n"
        "(822)516-8895 Jenna Doh 30 n"
        "(822)896-5453 Emily Saks 43 n"
}

所以我写的这个函数似乎不起作用，我确定有更简单的方法，但我无法弄清楚。

void parse_string(string data, vector <client> &clients)
{
    string temp;
    string temp1;
    string temp2;
    string temp3;
    int i = 0;
    int j = 0;
    int k = 0;
    int l = 0;
    while (i < data.length())
    {
        if (data.at(i) != ' ')
        {
            temp.push_back(data.at(i));
            j++;
        }
        else
        {
            clients.at(i).PhoneNumber = temp;
        }
    }
    if (data.at(j) != ' ')
    {
        temp1.push_back(data.at(j));
        k++;
    }
    else
    {
        clients.at(i).FirstName = temp1;
    }
    if (data.at(k) != ' ')
    {
        temp2.push_back(data.at(k));
        l++;
    }
    else
    {
        clients.at(i).LastName = temp2;
    }
    if (data.at(l) != ' ')
    {
        temp3.push_back(data.at(l));
    }
    else
    {
        clients.at(i).Age = temp3;
    }
    i++;
}

尝试使用 istringstream 对象：

void parse_string(string data, vector <client> & clients) {
  istringstream iss(data);
  for (size_t i=0; iss >> clients.at(i).PhoneNumber; ++i) {
    iss >> clients.at(i).FirstName
        >> clients.at(i).LastName
        >> clients.at(i).Age;
  }
}

你可以试试这段代码：

 void parse_string(string data, vector <client> & clients)
 {
     struct client tempS;
     istringstream iss(data);
     for (size_t i=0; iss >> tempS.PhoneNumber; ++i)
     {
         iss >> tempS.FirstN >> tempS.LastN >> tempS.Age;
         clients.push_back(tempS);
     }
 }

测试代码

vector <client>::iterator it = clients.begin();
     for(; it != clients.end(); ++it )
    {
        cout << it->PhoneNumber << " "
             << it->FirstN << " "
             << it->LastN << " "
             << it->Age << endl;
    }