平均值的C++数组循环

C++ Array loop for average

本文关键字：循环 数组 C++ 平均值      更新时间：2023-10-16

我目前正在尝试使用C++。到目前为止，我已经学会了制作一个程序，允许我输入10个变量和5个已经赋值的变量，然后找到这些数字的平均值。然而，我不知道如何做到这一点，我已经为数组做了一个for循环，但似乎没有找到平均答案。下面的代码出了什么问题？这就是我目前所拥有的：

#include <iostream>
using namespace std;
int cole[10];
int sum = 0;
int main()
{
    int a = 10;
    int b = 10;
    int c = 10;
    int d = 10;
    int e = 35;
    cout << "Please input ten numbers, one at a time" << endl;
    cin >> cole[0];
    cin >> cole[1];
    cin >> cole[2];
    cin >> cole[3];
    cin >> cole[4];
    cin >> cole[5];
    cin >> cole[6];
    cin >> cole[7];
    cin >> cole[8];
    cin >> cole[9];
    cout << "There will now be 5 assigned variables, so that we have 15 variables" << endl;
    for(int x = 0; x < 10; x++ )
    {
        int sum = 0;
        cout << cole[x] << " ";
        sum += cole[x];
        cole[x]++;
    }
    sum += cole[0];
    cole[0]++;
    cout << "and " << a << " " << b << " " << c << " " << d << " " << e << endl;
    cout << "The average of these numbers is: ";
    sum = sum + a + b + c + d + e;
    cout << sum / 15;
}

提前感谢

请尝试此代码：IDEONE

#include <iostream>
using namespace std;
int cole[10];
int sum = 0;
int main()
{
    int a = 10;
    int b = 10;
    int c = 10;
    int d = 10;
    int e = 35;
    double avg = 0;
    cout << "Please input ten numbers, one at a time" << endl;
    for (int i=0;i<10;i++) {
        cin >> cole[i];
    }
    cout << "There will now be 5 assigned variables, so that we have 15 variables" << endl;
    for(int x = 0; x < 10; x++ )
    {
        cout << cole[x] << " ";
        sum += cole[x];
    }
    cout << "and " << a << " " << b << " " << c << " " << d << " " << e << endl;
    cout << "The average of these numbers is: ";
    sum = sum + a + b + c + d + e;
    avg = sum / 15.0;
    cout << avg;
}

请记住，平均值不应该是一个整数值，它会将数字四舍五入到底。记住，在循环中也可以将每个值输入到数组中，不要一个接一个地输入。您还在循环中一次又一次地声明"int sum=0"，因此全局和在循环中不可见。我也删除了一些不需要的代码。您可以查看它，欢呼

    #include <iostream>
using namespace std;
int coleCount = 10;
int cole[coleCount];
int sum = 0;
int main()
{
    int a = 10;
    int b = 10;
    int c = 10;
    int d = 10;
    int e = 35;
    cout << "Please input ten numbers, one at a time" << endl;
    for(int i = 0; i < coleCount; i++)
    {
      cin >> cole[i];  
    }
    cout << "There will now be 5 assigned variables, so that we have 15 variables" << endl;
    for(int i = 0; i < coleCount; i++ )
    {
        cout << cole[i] << " ";
        sum += cole[i];
        //cole[x]++; why are you incrementing this?
    }
    //sum += cole[0]; why?
    //cole[0]++; why?
    cout << "and " << a << " " << b << " " << c << " " << d << " " << e << endl;
    cout << "The average of these numbers is: ";
    sum += (a + b + c + d + e);
    cout << sum / 15;
}

在循环中去掉int sum = 0和cole[x]++;。同样如此损失：

sum += cole[0];
cole[0]++;

循环之后。

int sum = 0;

这需要在循环之外，您不断地重置总和。

您正在声明sum两次。从for循环内部删除声明！

for(int x = 0; x < 10; x++ )
{        
    cout << cole[x] << " ";
    sum += cole[x];
    cole[x]++;
}

固定代码：

#include <iostream>
using namespace std;
int cole[10];
int sum = 0;
int main()
{
    int a = 10;
    int b = 10;
    int c = 10;
    int d = 10;
    int e = 35;
    cout << "Please input ten numbers, one at a time" << endl;
    cin >> cole[0];
    cin >> cole[1];
    cin >> cole[2];
    cin >> cole[3];
    cin >> cole[4];
    cin >> cole[5];
    cin >> cole[6];
    cin >> cole[7];
    cin >> cole[8];
    cin >> cole[9];
    cout << "There will now be 5 assigned variables, so that we have 15 variables" << endl;

    int sum = 0;  //initialize sum outside the for loop
    for(int x = 0; x < 10; x++ )
    {
        cout << cole[x] << " ";
        sum += cole[x];
        cole[x]++;
    }
    //sum += cole[0];  //this seems unnecessary
    //cole[0]++;
    cout << "and " << a << " " << b << " " << c << " " << d << " " << e << endl;
    cout << "The average of these numbers is: ";
    sum = sum + a + b + c + d + e;
    cout << sum / 15;
}
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