将一些数据推送到 Lua 调用函数

Push some data to Lua call function

本文关键字:Lua 调用 函数 数据      更新时间:2023-10-16

我有两个文件 - 一个用于执行Lua脚本和脚本本身。

他们在这里:

主机.cpp

#include <lua.hpp>
#include <iostream>
using namespace std;
int someHandler(lua_State  *l)
{
    int argc = lua_gettop(l);
    for (int i = 0; i < argc; i++)
    {
        cout << "ARG[" << i + 1 << "] = " << lua_tostring(l, i + 1) << endl;
    }
    lua_pushstring(l, "m_pi");
    //lua_pop(l, argc - 1);
    //lua_pushnumber(l, 3.14);
    return argc;
}
int main()
{
    lua_State *l = lua_open();
    luaL_openlibs(l);
    lua_register(l, "moo", someHandler);
    luaL_dofile(l, "script.lua");
    lua_close(l);
    return 0;
}

脚本.lua

res = moo("hello", "world");
print(moo());
for k, v in res do
    print(k.." = "..v);
end

编译host.cppg++ host.cpp -o host.elf -I/usr/include/lua5.1 -llua5.1 .

运行host.elf的结果是:

ARG[1] = hello
ARG[2] = world
<n>

虽然它应该是:

ARG[1] = hello
ARG[2] = world
m_pi

我做错了什么?

逐行说明:

--This calls moo with two arguments
--(ignore the assignment for now, we will come back to that)
res = moo("hello", "world");

控制权转移到C++:

//the stack of l looks like this: ["hello", "world"]
int someHandler(lua_State  *l)
{
    int argc = lua_gettop(l); //int argc = 2;
    //This loop prints:
    //"ARG[1] = hellon"
    //"ARG[2] = worldn"
    for (int i = 0; i < argc; i++)
    {
        cout << "ARG[" << i + 1 << "] = " << lua_tostring(l, i + 1) << endl;
    }
    //This pushes "m_pi" on to the stack:
    lua_pushstring(l, "m_pi");
    //The stack now looks like ["hello", "world", "m_pi"]
    //Returns 2.
    //Lua will treat this as a function which
    //returns the top two elements on the stack (["world", "m_pi"])
    return argc;
}

控制返回到 lua:

--Assigns the first result ("world") to res, discards the other results ("m_pi")
res = moo("hello", "world");
--Calls `moo` with zero arguments.
--This time, `lua_gettop(l)` will evaluate to `0`,
--so the for loop will not be entered,
--and the number of results will be taken to be `0`.
--The string pushed by `lua_pushstring(l, "m_pi")` will be discarded.
--`moo()` returns no results, so `print` prints nothing.
print(moo());
--WTF??: res = "world", which is a string, not an expression which evaluates to
--a loop function, a state variable, and a element variable.
--The for loop will raise in an error when it 
--attempts to call a copy of `res` (a string)
for k, v in res do
    print(k.." = "..v);
end