GoogleTest无法使用自定义比较运算符

GoogleTest fails to use custom comparison operator

本文关键字：自定义 比较 运算符 GoogleTest      更新时间：2023-10-16

我想在谷歌测试中对我的Word结构进行简单的测试。为了使测试代码变得更简单、更短，我决定编写一个比较运算符（尽管我并不真的需要），并根据初级读本使用ASSERT_EQ。尽管一切看起来都很好，但我还是收到了一个编译器错误：

/* Word.h */
namespace tgs {
struct Word {
    //something here
    Word();
    virtual ~Word();
    bool operator== (Word& rhs);
};
}
/* Word.cpp */
namespace tgs {
bool Word::operator== (Word& rhs){
  return true; //there are actual member comparisons here
}
}

/* TextAreaShould_test.cc */
TEST_F(TextAreaShould, DoSomething) {
  Word w1, w2;
  if(w1 == w2){ //compiles and runs ok
    0;
  }
  ASSERT_EQ(w1, w2); //produces following error
}

编译器错误：

[ 86%] Building CXX object CMakeFiles/tests/TextAreaShould.test.dir/tests/TextAreaShould_test.cc.o
/usr/bin/c++    -I/home/nietaki/zpp/TheGameShow_build -I/home/nietaki/zpp/TheGameShow -I/home/nietaki/zpp/TheGameShow/google_mock/include -I/home/nietaki/zpp/TheGameShow/google_mock/gtest/include -I/usr/local/include   -o CMakeFiles/tests/TextAreaShould.test.dir/tests/TextAreaShould_test.cc.o -c /home/nietaki/zpp/TheGameShow/tests/TextAreaShould_test.cc
In file included from /home/nietaki/zpp/TheGameShow/tests/TextAreaShould_test.cc:8:
/home/nietaki/zpp/TheGameShow/google_mock/gtest/include/gtest/gtest.h: In function ‘testing::AssertionResult testing::internal::CmpHelperEQ(const char*, const char*, const T1&, const T2&) [with T1 = tgs::Word, T2 = tgs::Word]’:
/    home/nietaki/zpp/TheGameShow/google_mock/gtest/include/gtest/gtest.h:1363:   instantiated from ‘static testing::AssertionResult testing::internal::EqHelper<lhs_is_null_literal>::Compare(const char*, const char*, const T1&, const T2&) [with T1 = tgs::Word, T2 = tgs::Word, bool lhs_is_null_literal = false]’
/home/nietaki/zpp/TheGameShow/tests/TextAreaShould_test.cc:112:   instantiated from here
/home/nietaki/zpp/TheGameShow/google_mock/gtest/include/gtest/gtest.h:1326: error: no match for ‘operator==’ in ‘expected == actual’
/home/nietaki/zpp/TheGameShow/renderer/textarea/Word.h:25: note: candidates are: bool tgs::Word::operator==(tgs::Word&)

我还尝试将比较运算符放在类之外，而不是作为成员，但这似乎没有多大区别。我试着按照初级读本做每件事，但可能出了问题。

比较运算符不会更改任何参数，因此它可以是const，如谷歌测试所使用的：

struct Word {
    Word();
    virtual ~Word();
    bool operator== (const Word& rhs) const;
};

一切都很顺利。

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