比较两个字符串add(空格，逗号，点等)c++

Compare two strings add(empty space, commas, dots, etc) c++

本文关键字：逗号 点等 c++ 空格 字符串 两个 比较 add      更新时间：2023-10-16

嗨，我希望有人能帮助我，我正试图修复我的字符串输出，我得到一个输出，但它全部捣碎成一个长字符串没有空格等，所以我试图使用旧字符串，以前有逗号空格等，并将它们替换为新的。我真的不知道如何去做这件事，我在c++中尝试过，如果我在我的程序中运行下面的代码，它会在我身上崩溃，我不知道如何修复它。

string input2 = "chq pste uwdn or mfwiejjne
u aaul mvabe mrv po zso, jnp kg co urfrsrvwn,
azh s bmmpd lanmf kuupv chqvw, xf opsh azh ojtfpwb mmhw;
wizi tnaz vgfs imdu i tenn ttijn, a tmnn fav lqe tsfny niw,
jnp paee mpgwe ur lqe niw uogh yuapi.
swd u wzjlx lsee esen pqeun ttijn, fav hnaoi uxmqw vaobtawg epgf,
ddshyizk xaoy xzn vqmdb or xzn mavfrns xg fhqvw chq gjrcwil bizkk;
chqvw vipraphf’w sul m kdrmyij, jnp rgxn m tmapxi yuoi,
efm ehifrns jmul aj lqe xmfwef’w ornsw.
a fixp saiei swd ss fxw, rsj jlieqb nukzc azh vjy
u lwjr xecn wmxwa lmthrns aach xso bogrvb bk xzn stsjn;
wtmdn i exswd ar lqe dssmwmc, ga oz xzn pmzwvezxk prqc,
a qemv ac iz xzn dqih qemvl’b cavw.";

string result = "THELAKEISLEOFINNISFREEIWILLARISEANDGONOWANDGOTOINNISFREEANDASMALLCAB
INBUILDTHEREOFCLAYANDWATTLESMADENINEBEANROWSWILLIHAVETHEREAHIVEFORTH
EHONEYBEEANDLIVEALONEINTHEBEELOUDGLADEANDISHALLHAVESOME
PEACETHEREFORPEACECOMESDROPPINGSLOWDROPPINGFROMTHEVEILSOFTHEMORNINGTOWHERETHE
CRICKETSINGSTHEREMIDNIGHTSALLAGLIMMERANDNOONAPURPLEGLOWANDEVENINGFULLOFTHELINNET
SWINGSIWILLARISEANDGONOWFORALWAYSNIGHTANDDAYIHEARLAKEWATERLAPPINGWITHLOWSOUNDSB
YTHESHOREWHILEISTANDONTHEROADWAYORONTHEPAVEMENTSGREYIHEARITINTHEDEEPHEARTSCORE";
string original = input2; //original unchanged text with spaces, commas etc
string tempResult = result; //the new output without spaces, commas, dots etc
string fixed = ""; //string to be altered with spaces, commas etc
int originalSize = input2.size();
int i = 0, j = 0;
for(i, j; i < originalSize ;i++)
{
  if(isalnum(original[i]) || !original[i] == ' ')
{
  fixed += tempResult[j];
  j++;
}
else
{
  fixed += tempResult[j];
}
}

正如评论中所指出的，提供一个最小的，完整的和可验证的例子会让你更容易理解你的问题，但我想我明白你想做什么。对代码进行最小的修改，一个解决方案可能是:

#include <iostream>
#include <string>
using namespace std;
string original = "xxxx, x xxxxx, xx x xxxxxx xxxxxxxx.";
string letters = "ThisIthinkisabetterquestion";
string desired = "This, I think, is a better question.";
int main()
{
    string fixed;
    int i, j;
    int originalSize = original.size();
    for(i=j=0; i < originalSize ;i++)
    {
        if(!isalnum(original[i]))
        {
          fixed += original[i];
        }
        else
        {
          fixed += letters[j++];
        }
    }
    cout << fixed << endl;
    cout << desired << endl;
    return 0;
}
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