c++ tga解析某些分辨率的incorrect_color/distortion

我想得到一些帮助我的问题与。tga文件格式解析。我有代码，我用了很长时间:

            int fileLength = Input.tellg();
            vector<char> tempData;
            tempData.resize(fileLength);
            Input.seekg(0);
            Input.read(&tempData[0], fileLength);
            Input.close();
            // Load information about the tga, aka the header.
            // Seek to the width.
            w = byteToUnsignedShort(tempData[12], tempData[13]);
            // Seek to the height.
            h = byteToUnsignedShort(tempData[14], tempData[15]);
            // Seek to the depth.
            depth = unsigned(tempData[16]);
            // Mode = components per pixel.
            md = depth / 8;
            // Total bytes = h * w * md.
            t = h * w * md;
            //Delete allocated data, if need to
            clear();
            //Allocate new storage
            data.resize(t);
            // Copy image data.
            for(unsigned i = 0, s = 18; s < t + 18; s++, i++)
                data[i] = unsigned char(tempData[s]);
            // Mode 3 = RGB, Mode 4 = RGBA
            // TGA stores RGB(A) as BGR(A) so
            // we need to swap red and blue.
            if(md > 2)
            {
                char aux;
                for(unsigned i = 0; i < t; i+= md)
                {
                    aux = data[i];
                    data[i] = data[i + 2];
                    data[i + 2] = aux;
                }
            }

但是对于某些图像分辨率(主要是奇数和非pot分辨率)，它偶尔会失败。它导致扭曲的图像(与对角线图案)或错误的颜色。上次我遇到它-它是9x924bpp的图像显示奇怪的颜色。

我在windows上(所以它意味着小端)，用opengl渲染(我考虑到alpha通道存在，当用glTexImage2D传递图像数据时)。我用photoshop保存我的图像，而不是设置RLE标志。此代码总是读取正确的图像分辨率和颜色深度。

图片引起麻烦的例子:http://pastie.org/private/p81wbh5sb6coldspln6mw

加载有问题的图像后，此代码:

for(unsigned f = 0; f < imageData.w * imageData.h * imageData.depth; f += imageData.depth)
{
    if(f % (imageData.w * imageData.depth) == 0)
        writeLog << endl;
    writeLog << "[" << unsigned(imageData.data[f]) << "," << unsigned(imageData.data[f + 1]) << "," << unsigned(imageData.data[f + 2]) << "]" << flush;
}

输出:

[37,40,40][37,40,40][37,40,40][37,40,40][37,40,40][37,40,40][37,40,40][37,40,40][37,40,40]
[37,40,40][173,166,164][93,90,88][93,90,88][93,90,88][93,90,88][93,90,88][88,85,83][37,40,40]
[37,40,40][228,221,219][221,212,209][221,212,209][221,212,209][221,212,209][221,212,209][140,134,132][37,40,40]
[37,40,40][228,221,219][221,212,209][221,212,209][221,212,209][221,212,209][221,212,209][140,134,132][37,40,40]
[37,40,40][228,221,219][221,212,209][221,212,209][221,212,209][221,212,209][221,212,209][140,134,132][37,40,40]
[37,40,40][228,221,219][221,212,209][221,212,209][221,212,209][221,212,209][221,212,209][140,134,132][37,40,40]
[37,40,40][228,221,219][221,212,209][221,212,209][221,212,209][221,212,209][221,212,209][140,134,132][37,40,40]
[37,40,40][237,232,230][235,229,228][235,229,228][235,229,228][235,229,228][235,229,228][223,214,212][37,40,40]
[37,40,40][37,40,40][37,40,40][37,40,40][37,40,40][37,40,40][37,40,40][37,40,40][37,40,40]

所以我猜它确实读取正确的数据。这就引出了opengl;

glGenTextures(1, &textureObject);
glBindTexture(GL_TEXTURE_2D, textureObject);
glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_WRAP_S, GL_REPEAT);
glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_WRAP_T, GL_REPEAT);
GLenum in_comp_mode, comp_mode;
if(linear) //false for that image
    glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MAG_FILTER, GL_LINEAR);
else
    glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MAG_FILTER, GL_NEAREST);
glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, GL_LINEAR);
//i don't use 1 or 2 - channel textures, so it's always 24 or 32bpp
    if(imageData.depth == 24)
    {
        in_tex_mode = GL_RGB8;
        tex_mode = GL_RGB;
    }
    else
    {
        in_tex_mode = GL_RGBA8;
        tex_mode = GL_RGBA;
    }
glTexImage2D(GL_TEXTURE_2D, 0, in_tex_mode, imageData.w, imageData.h, 0, tex_mode, GL_UNSIGNED_BYTE, &imageData.data[0]);
glBindTexture(GL_TEXTURE_2D, NULL);

纹理压缩代码被省略了，因为它对那个纹理来说不是活动的。