程序因二进制错误而停止

我被要求为我的推荐课程创建一个汽油泵程序，但我在运行它时遇到了问题，目前这是编译器在尝试编译代码完整构建对话时输出的主要内容

1> m:\visual studio 2010\projects\referration\referration\main.cpp（56）：错误C2678:二进制">>"：找不到接受类型为"std:：istream"的左侧操作数的运算符（或者没有可接受的转换）

#include <iostream>
#include <istream>
#include <ostream>
#include <fstream>
#include <ctime>
#include <cmath>
#include <string>
#include <Windows.h>
using namespace std;
int reciept();
int pump;
int petrol;
int main()
{
    bool exit = false;
    int code;
    string p1w ("Waiting");
    string p2w ("Waiting");
    string p3w ("Waiting");
    string p4w ("Waiting");
    string p1r ("Ready");
    string p2r ("Ready");
    string p3r ("Ready");
    string p4r ("Ready");
    if (GetAsyncKeyState(VK_ESCAPE))
    {
        exit = true;
    }
    cout << "***************************************************" << endl;
    cout << "*Liquid Gold v1.0.0 Last revised 18/07/13         *" << endl;
    cout << "*The process of processing transactions is simple,*" << endl;
    cout << "*activate a pump by entering its code shown below.*" << endl;
    cout << "*After pump operation is verified (generally 10   *" << endl;
    cout << "*seconds though this may vary) the attendant      *" << endl;
    cout << "* will be able to enter the amount of petrol to 3 *" << endl;
    cout << "*decimal places which will then be converted based*" << endl;
    cout << "*on a predetermined price (which can be altered in*" << endl;
    cout << "*price.txt) and once this process is complete a   *" << endl;
    cout << "*receipt will be created (you will need seperate  *" << endl;
    cout << "*software in order to print this recipt) and the  *" << endl;
    cout << "*transaction will be terminated.                  *" << endl;
    cout << "*© Simple Software Solutions 2013                 *" << endl;
    cout << "***************************************************" << endl << endl;
    system("Pause");
    while (exit == false)
    {
        cout << "       Pump (1) - " << p1w << "        Pump (2) - " << p2w << endl << endl << endl;
        cout << "       Pump (3) - " << p3w << "        Pump (4) - " << p4w << endl << endl << endl;
        cin >> "Please enter a pump code:" >> code;
        if (code == 1)
        {
            swap (p1w, p1r);
            pump = 1;
            cin >> "Please enter the amount of petrol deposited" >> petrol;
            break;
        } 
        else if (code == 2)
        {
            swap (p2w, p2r);
            pump = 2;
            cin >> "Please enter the amount of petrol deposited" >> petrol;
            break;
        }
        else if (code == 3)
        {
            swap (p3w, p3r);
            pump = 3;
            cin >> "Please enter the amount of petrol deposited" >> petrol;
            break;
        }
        else if (code == 4)
        {
            swap (p4w, p4r);
            pump = 4;
            cin >> "Please enter the amount of petrol deposited" >> petrol;
            break;
        }
        else
        {
            cout << "Invalid pump code entered";
        }
        reciept();
        {
             ofstream transactions;
             transactions.open ("reciept.txt");
             transactions << "****************************************************/n";
             transactions << "                        SALE                        /n";
             transactions << "****************************************************/n /n";
        }
    }
    return 0;
}

我环顾四周，我能找到的唯一错误解决方案是包括我已经做过的，我看不到任何其他解决方案。

有谁比我更善于观察，愿意仔细看看，告诉我哪里出了问题？

我也知道我的代码是一个低效的烂摊子，对此我深表歉意。