Extending Python 3 with C++
Extending Python 3 with C++
我正在尝试使用这里给出的指令扩展Python 3,我很有信心到目前为止我已经正确地遵循了指令,但它要求我包含以下代码:
PyMODINIT_FUNC
PyInit_spam(void)
{
PyObject *m;
m = PyModule_Create(&spammodule);
if (m == NULL)
return NULL;
SpamError = PyErr_NewException("spam.error", NULL, NULL);
Py_INCREF(SpamError);
PyModule_AddObject(m, "error", SpamError);
return m;
}
我在MSVC++2010上写这篇文章,它警告我&spammodule是未定义的(模块的名称是spammodule.cpp),但它在指令中没有定义它,所以我认为它应该自动将其识别为模块的名称。
完整代码为:
#include <Python.h>
#include <iostream>
using namespace std;
static PyObject *SpamError;
int main()
{
cout << "Test" << endl;
system("PAUSE");
return(0);
}
static PyObject *spam_system(PyObject *self, PyObject *args)
{
const char *command;
int sts;
if (!PyArg_ParseTuple(args, "s", &command))
return NULL;
sts = system(command);
return PyLong_FromLong(sts);
}
PyMODINIT_FUNC
PyInit_spam(void)
{
PyObject *m;
m = PyModule_Create(&spammodule);
if (m == NULL)
return NULL;
SpamError = PyErr_NewException("spam.error", NULL, NULL);
Py_INCREF(SpamError);
PyModule_AddObject(m, "error", SpamError);
return m;
}
您仍在编写C++,因此仍需要在某处声明spammodule
。稍后在同一页上给出:
static struct PyModuleDef spammodule = {
PyModuleDef_HEAD_INIT,
"spam", /* name of module */
spam_doc, /* module documentation, may be NULL */
-1, /* size of per-interpreter state of the module,
or -1 if the module keeps state in global variables. */
SpamMethods
};
No No No,PyModule_Create()
接受指向模块定义结构的指针,与源文件的名称完全无关。
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