sqlite c++体系结构x86_64的未定义符号
sqlite c++ Undefined symbols for architecture x86_64
我正在Mac osx上运行一个sqlite c++演示。我从下面显示的网页上复制了代码。
参考:http://www.tutorialspoint.com/sqlite/sqlite_c_cpp.htm
源代码是
//
#include <stdio.h>
#include <stdlib.h>
#include <sqlite3.h>
#include <fstream>
#include <string>
using namespace std;
static int callback(void *NotUsed, int argc, char **argv, char **azColName){
int i;
for(i=0; i<argc; i++){
printf("%s = %sn", azColName[i], argv[i] ? argv[i] : "NULL");
}
printf("n");
return 0;
}
int main(int argc, char* argv[])
{
sqlite3 *db;
char *zErrMsg = 0;
int rc;
char *sql;
string str;
/* Open database */
rc = sqlite3_open("test.db", &db);
if( rc ){
fprintf(stderr, "Can't open database: %sn", sqlite3_errmsg(db));
exit(0);
}else{
fprintf(stdout, "Opened database successfullyn");
}
/* Create SQL statement */
str = "CREATE TABLE location(country text, state text, city text );CREATE TABLE weather(temp real, tempunit text);";
strcpy(sql,str.c_str());
/* Execute SQL statement */
rc = sqlite3_exec(db, sql, callback, 0, &zErrMsg);
if( rc != SQLITE_OK ){
fprintf(stderr, "SQL error: %sn", zErrMsg);
sqlite3_free(zErrMsg);
}else{
fprintf(stdout, "Table created successfullyn");
}
sqlite3_close(db);
return 0;
}
输出为
g++ sqlite.cpp -v
Apple LLVM version 5.1 (clang-503.0.40) (based on LLVM 3.4svn)
Target: x86_64-apple-darwin13.3.0
Thread model: posix
"/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/clang" -cc1 -triple x86_64-apple-macosx10.9.0 -emit-obj -mrelax-all -disable-free -disable-llvm-verifier -main-file-name sqlite.cpp -mrelocation-model pic -pic-level 2 -mdisable-fp-elim -masm-verbose -munwind-tables -target-cpu core2 -target-linker-version 236.3 -v -resource-dir /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../lib/clang/5.1 -stdlib=libc++ -fdeprecated-macro -fdebug-compilation-dir /Users/zerocraft/KuaiPan/Course/ECEN489/test -ferror-limit 19 -fmessage-length 166 -stack-protector 1 -mstackrealign -fblocks -fobjc-runtime=macosx-10.9.0 -fencode-extended-block-signature -fcxx-exceptions -fexceptions -fdiagnostics-show-option -fcolor-diagnostics -vectorize-slp -o /var/folders/1d/dbmt5pd519bcp0dqr5vv76_c0000gn/T/sqlite-742d60.o -x c++ sqlite.cpp
clang -cc1 version 5.1 based upon LLVM 3.4svn default target x86_64-apple-darwin13.3.0
ignoring nonexistent directory "/usr/include/c++/v1"
ignoring nonexistent directory "/usr/local/include"
#include "..." search starts here:
#include <...> search starts here:
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../lib/c++/v1
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../lib/clang/5.1/include
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/include
/usr/include
/System/Library/Frameworks (framework directory)
/Library/Frameworks (framework directory)
End of search list.
"/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/ld" -demangle -dynamic -arch x86_64 -macosx_version_min 10.9.0 -o a.out /var/folders/1d/dbmt5pd519bcp0dqr5vv76_c0000gn/T/sqlite-742d60.o -lc++ -lSystem /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../lib/clang/5.1/lib/darwin/libclang_rt.osx.a
Undefined symbols for architecture x86_64:
"_sqlite3_close", referenced from:
_main in sqlite-742d60.o
"_sqlite3_errmsg", referenced from:
_main in sqlite-742d60.o
"_sqlite3_exec", referenced from:
_main in sqlite-742d60.o
"_sqlite3_free", referenced from:
_main in sqlite-742d60.o
"_sqlite3_open", referenced from:
_main in sqlite-742d60.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
我已经在笔记本电脑上安装了sqlite库。有人能解释一下吗?谢谢
您没有针对sqlite库进行链接。你遵循的教程说要这样做:
g++ test.c -lsqlite3
但你做到了:
g++ sqlite.cpp -v
选项"-lsqlite3"告诉链接器链接到sqlite3库中。否则,它将无法找到在此库中定义的符号。
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