C++正在检查用户是否输入了有效答案

C++ Checking if a user input a valid answer

本文关键字：输入有效答案是否用户检查 C++ 更新时间：2023-10-16

当提示时，我需要检查他们是否输入了快乐、悲伤或疯狂：输入心情（快乐、悲伤、疯狂）这是我迄今为止的代码count=0；而（计数<1）{

    cout << ", How are you feeling today? (happy,sad,mad)" << endl;
    cin >> mood;
    if (mood == sad){
        cout << "im sorry you're feeling sad" << endl;
            count++;
    }
    else if (mood == happy) {
        cout << "I'm glad you're feeling happy!" << endl;
            count++;
    }
    else if (mood == mad){
        cout << "Don't be angry, there's so many happy things in life!" << endl;
    }
    else{
        cout << " invalid input " << endl;
        count = 0;
    }
    }

但如果我输入快乐、悲伤或疯狂，它就会进入无效输入。我还尝试为它们声明字符串变量，比如string happy=快乐；string sad=悲伤；string mad=疯狂；

两件事：

确保您正在正确初始化字符串的
```
string happy = "happy";
```
尝试使用string.compare()而不是==
```
mood.compare(happy);
```

有关更多详细信息：http://www.cplusplus.com/reference/string/string/compare/