编译器构造 - 为什么这个C++程序不能编译？

compiler construction - Why won't this C++ program compile?

本文关键字：程序 C++ 不能 编译 为什么 编译器      更新时间：2023-10-16

这是我要编译的程序。

#include <iostream>
#include <string>
#include <vector>
#include <unistd.h>
using namespace std;
vector<string> paramlist;
const char *programname = "abc";
const char **args = new const char* [paramlist.size()+2];   // extra room for program name and sentinel
args [0] = programname;         // by convention, args[0] is program name
for (int j = 0;  j < paramlist.size()+1;  ++j)     // copy args
args [j+1] = paramlist[j] .c_str();
args [paramlist.size()+1] = NULL;  // end of arguments sentinel is NULL
execv (programname, (char **)args);

当我尝试编译它时，我得到这些错误信息:

test.cpp:11: error: expected constructor, destructor, or type conversion before ‘=’ token
test.cpp:12: error: expected unqualified-id before ‘for’
test.cpp:12: error: expected constructor, destructor, or type conversion before ‘<’ token
test.cpp:12: error: expected unqualified-id before ‘++’ token
test.cpp:15: error: array bound is not an integer constant
test.cpp:15: error: expected constructor, destructor, or type conversion before ‘=’ token
test.cpp:17: error: expected constructor, destructor, or type conversion before ‘(’ token

你至少需要一个int main函数

您的程序包含代码，但它需要包含在函数中。尝试在using namespace std;行之后使用int main这样的函数包装所有代码。

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