Visual Studio c++对重载函数的歧义调用

编辑:我张贴了整个类(条纹一些错误无关的东西出来)

我创建了以下类:

class packet
{public:char *  buffer;
    int     size;
    int     data;
    packet();
    packet(packet &text, int length=-1);
    packet(char * text, int length=-1);
    packet(int val);
    packet(char c);
    packet(double d);
    packet(float f);
    ~packet();
    packet &    operator=       (packet &text);
    packet      operator+       (packet &text);
    packet &    operator+=      (packet &text);
    packet &    operator|=      (packet &text);
    bool        operator==      (packet &text);
    bool        operator*=      (packet &text);
    bool        operator!=      (packet &text);
                operator char*  () const;
                operator int    () const;
                operator float  () const;
    char        operator []     (int pos)  const;
};

我这样使用这个类:

    packet p = packet();

或

return packet();

和Visual Studio给了我这个错误:

test.cpp(162): error C2668: 'packet::packet' : ambiguous call to overloaded function
...packet.h(26): could be 'packet::packet(float)'
...packet.h(23): or       'packet::packet(int)'
...packet.h(22): or       'packet::packet(char *,int)'

有人知道我在这里做错了什么吗?为什么会有歧义?

PS:我认为这与底部的4个操作符有关，但我对重载这些操作符有点模糊…

解决方案:我通过将一些构造函数标记为显式来使其工作:

class packet
{public:char *  buffer;
    int     size;
    int     data;
    packet();
    packet(packet &text, int length=-1);
    explicit packet(char * text, int length=-1);
    explicit packet(int val);
    explicit packet(char c);
    explicit packet(double d);
    explicit packet(float f);
    ~packet();
    packet &    operator=       (packet &text);
    packet      operator+       (packet &text);
    packet &    operator+=      (packet &text);
    packet &    operator|=      (packet &text);
    bool        operator==      (packet &text);
    bool        operator*=      (packet &text);
    bool        operator!=      (packet &text);
                operator char*  () const;
                operator int    () const;
                operator float  () const;
    char        operator []     (int pos)  const;
};