这两个功能能合二为一吗?

我刚刚完成了下面代码中注释块中描述的一个迷你任务，但是我一直试图通过将getRareDigits和displayRareDigits组合成一个函数来使代码更好。不管我做什么，逻辑总是会被打破。谁能给我解释一下这两个函数是否有可能结合在一起?谢谢^ _ ^

/*
    Written by: Stephanie Yumiko
* This program will ask the user
for a series of integers, defined by
the user.
* The program will display back to the
user the number of rare digits, digits
that only occur once in a single integer,
but not the rest. 
* The program will then sort the integers
based on the number of occurrences of
rare digits it contains, from greatest
to least.
*/
#include <iostream>
using namespace std;
bool num_contains(int, int);
void showRareDigits(int*, int);
void sortRareDigits(int*, int* , int);
bool num_contains(int digit, int n) {
    while (n) {
        if (digit == n % 10) return true;
        n /= 10;
    }
    return false;
}
void getRareDigits(int *arr, int *ordered, int len) {
    for (int index = 0; index < len; ++index) {
        int n = arr[index];
        if (n < 0)
            n *= -1;
        int d = 0;
        while (n) {
            d = n % 10;
            int i;      // keep track of loop counter outside the loop
            int stop = 0; // to break out loop
            for (i = 0; i < len; ++i) {
                if (i != index && num_contains(d, arr[i]))
                    stop = 1;
            }
            // only increment the array if the loop exited before
            // completing (implying the goto would have happened)
            if (!stop) {
                ++ordered[index];
            }
            // always execute 
            n /= 10;
        }
    }
    for (int i = 0; i<len; i++) {
        for (int j = 0; j<len - i - 1; j++) {
            if (ordered[j]<ordered[j + 1]) {
                int temp = ordered[j];
                ordered[j] = ordered[j + 1];
                ordered[j + 1] = temp;
                int temp2 = arr[j];
                arr[j] = arr[j + 1];
                arr[j + 1] = temp2;
            }
        }
    }
    cout << "nArray after sort:n";
    for (int i = 0; i < len; i++) {
        cout << arr[i] << endl;
    }
}
void showRareDigits(int* iAry, int size) {
    const int size2 = 10;
    int* tmpAry = new int[size];
    int totalCount[size2] = { 0 };
    int currentCount[size2] = { 0 };
    int totalUncommon = 0;
    int i, j;
    int* ordered;
    ordered = new int[size];
    for (i = 0; i < size; i++) {
        ordered[i] = 0;
        tmpAry[i] = iAry[i];
        if (tmpAry[i] < 0)
            tmpAry[i] *= -1;
        for (j = 0; j < size2; j++)
            currentCount[j] = 0;
        if (tmpAry[i] == 0) {
            currentCount[0] = 1;
        }
        while (tmpAry[i] / 10 != 0 || tmpAry[i] % 10 != 0){
            currentCount[tmpAry[i] % 10] = 1;
            tmpAry[i] /= 10;
        }
        for (j = 0; j < size2; j++) {
            totalCount[j] += currentCount[j];
        }
    }
    for (i = 0; i < size2; i++) {
        if (totalCount[i] == 1) {
            totalUncommon++;
        }
    }
    cout << "nTotal rare digits: " << totalUncommon << endl
        << "nThe rare digits:n";
    if (totalUncommon == 0) {
        cout << "nNo rare digits found.";
    }
    else {
        for (i = 0; i < size2; i++) {
            if (totalCount[i] == 1) {
                cout << i << endl;
            }
        }
    }
    getRareDigits(iAry, ordered, size);
    delete[] tmpAry;
    delete[] ordered;
    return;
}

int main() {    
    int size;
    int* arr;
    cout << "Enter # of integers: ";
    cin >> size;
    arr = new int[size];
    for (int i = 0; i < size; i++) {
        cout << "Enter the value for #" << i << " : ";
        cin >> arr[i];
    }
    cout << "Array before sorting:n";
    for (int i = 0; i < size; i++) {
        cout << arr[i] << endl;
    }
    showRareDigits(arr, size);  
    delete[] arr;
    return 0;
}