使用数组输出错误的文件

Incorrect file output using arrays

本文关键字：文件 错误 输出 数组      更新时间：2023-10-16

大家好，我刚刚学习我的第一个编程语言，刚刚纠正了我的代码中的一个错误，只是留下了另一个错误。谢天谢地，这是我需要解决的最后一个问题，但我自己做起来有点麻烦。

程序将读取客户号码和与每个客户号码相关的费用。然后，它将添加财务费用，输出所有费用，合计所有内容，并将每个客户的新余额与他们的ID号以相反顺序保存到文件中。

beginningbalance.dat看起来像

111
200.00
300.00
50.00
222
300.00
200.00
100.00

和newbalance .dat应该看起来像

222
402.00
111
251.00

除了取决于在文件写入循环中放置"count——"的位置外，我最终得到

222
402.00
111
251.00
-858993460
-92559631349317830000000000000000000000000000000000000000000000.00

我不知道该怎么做才能去掉这些额外的值。有什么建议吗?

我的代码

#include <iostream>
#include <fstream>
#include <iomanip>
using namespace std;

int main()
{
  int count = 0;
  const int size = 100;
  double customer_beg_balance, customer_purchases, customer_payments, finance_charge_cost, finance_charge = .01;
  int customer_number[size];
  double new_balance[size];
  double total_beg_balances=0,total_finance_charges=0,total_purchases=0,total_payments=0,total_end_balances=0;

  ifstream beginning_balance;
  beginning_balance.open("beginningbalance.dat");
  while(beginning_balance>>customer_number[count])
    {
        beginning_balance >> customer_beg_balance;
        beginning_balance >> customer_purchases;
        beginning_balance >> customer_payments;
        finance_charge_cost = customer_beg_balance * finance_charge;
        new_balance[count] = customer_beg_balance + finance_charge_cost + customer_purchases - customer_payments; 
        total_beg_balances+=customer_beg_balance;
        total_finance_charges+=finance_charge_cost;
        total_purchases+=customer_purchases;
        total_payments+=customer_payments;
        total_end_balances+=new_balance[count];
        cout<<fixed<<setprecision(2)<<setw(8)<<"Cust No  "<<"Beg. Bal.  "<<"Finance Charge  "<<"Purchases  "<<"Payments  "<<"Ending Bal.n"
            <<customer_number[count]<<"        "<<customer_beg_balance<<"        "<<finance_charge_cost<<"       "<<customer_purchases<<"     "<<customer_payments<<"         "<<new_balance[count]<<endl;

        count++;                            
    }
  cout<<"nTotals     "<<total_beg_balances<<"        "<<total_finance_charges<<"       "<<total_purchases<<"     "<<total_payments<<"         "<<total_end_balances<<endl;
  ofstream new_balance_file;
  new_balance_file.open("NewBalance.dat");
  while(count >= 0)
  {
    count--;
    new_balance_file <<customer_number[count]<<endl;
    new_balance_file<< fixed<<setprecision(2)<<new_balance[count]<<endl;
  }

  new_balance_file.close();

system("pause");
        return 0;
 }

您的情况不对

 while(count >= 0)
 {
    count--;
    new_balance_file <<customer_number[count]<<endl;
    new_balance_file<< fixed<<setprecision(2)<<new_balance[count]<<endl;
 }

应该是count > 0而不是count >= 0。

这样count将遍历值n, n-1, ... 1，并且因为您在while语句的开始处对其进行递减，因此您将在循环中操作的值将是n-1, n-2.... 0，这正是您需要的。

顺便说一下，如果你的课程已经涵盖了for循环，并且你被允许使用它，那么它更合适，像这样

for(int i = count - 1; i >= 0; --i)
{
    use i instead of count here.
}

希望这对你有帮助，祝你学习顺利!

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