从输入文件中读取

您可以使用std::getline提取行，然后将行解析为由空格分隔的std::vector。那么你知道words.size() - 2的单词是名字的一部分。例如:

std::fstream in("in.txt");
std::string line;
// Extract each line from the file
while (std::getline(in, line)) {
  std::istringstream line_stream(line);
  // Now parse line_stream into a vector of words
  std::vector<std::string> words(std::istream_iterator<std::string>(line_stream),
                                 (std::istream_iterator<std::string>()));
  int name_word_count = words.size() - 2;
  if (name_word_count > 0) {
    // Concatenate the first name_word_count words into a name string
    // and parse the last two words as integers
  }
}

在我看来，您需要使用getline，然后解析这条线。解析它的一种解决方案可能是拆分在第一个数字前面划线，然后修剪前半部分，然后将其用作名称，并使用std::istringstream读取两个数字。这将会失败，当然，如果某人的名字中有数字，但是在我看来，这是一个合理的限制。换句话说，对于每一行，您可以这样做:

std::string::iterator first_digit
        = std::find_if( line.begin(), line.end(), IsDigit() );
if ( first_digit == line.end() ) {
    //  format error...
} else {
    name = trim( std::string( line.begin(), first_digit ) );
    std::istringstream parser( std::string( first_digit, line.end() ) );
    parser >> firstNumber >> secondNumber >> std::ws;
    if ( !parser || parser.get() != EOF ) {
        //  format error...
    } else {
        //  Do what ya gotta do.
    }
}

应该这样做:

std::string str;
while(getline(infile, str))
{
  std::string::size_type pos;
  pos = str.find_last_of(' ');
  if (pos == std::string::npos || pos < 1)
  {
      cout << "Something not right with this string: " << str << endl;
      exit(1);
  }
  int last_number = stoi(str.substr(pos));
  str = str.substr(0, pos-1);    // Remove the number and the space.
  pos = str.find_last_of(' ');
  if (pos == std::string::npos || pos < 1)
  {
      cout << "Something not right with this string: " << str << endl;
      exit(1);
  }
  int first_number = stoi(str.substr(pos));
  str = str.substr(0, pos-1); 
  // str now contains the "name" as one string. 
  // ... here you use last_number and first_number and str to do what you need to do. 
}

实际上，您可以使用getline();使用两个参数方法，传递一个流和'n'作为分隔符。

将整行赋值为一个字符串，然后使用空格分隔字符串，并将后两个字符串转换为整数。

1。打开文件

std::ifstream myFile("somewhere.txt");

2)。检查文件是否打开

if(myFile.is_open())

3)。读取直到文件结束

while(!myFile.eof())

4)。将名字读入名字数组

myFile >> firstName[numberOfPeople];

5)。将姓氏读入姓氏数组

myFile >> lastName[numberOfPeople];

6)。将整数读入整数数组

myFile >> integer[numberOfPeople];

7。)增加人数

numberOfPeople++;

8。)当while完成时，关闭file

myFile.close();

9。)如果文件未打开，则报告错误。

else
   std::cout << "nFile did not open. " << std::endl;

你可以使用getline函数，你只需要解析字符串。这可以使用strtok.

我已经实现了一个解决方案，你的问题(主要是我自己的学习)。它按预期工作，但感觉有点长。

#include<string>
#include<fstream>
#include<sstream>
#include<iostream>
#include<vector>
#include<algorithm>
#include<iterator>
struct PlayerData {
  std::string name;
  int number;
  int points;
};
std::ostream& operator<<(std::ostream& os, const PlayerData& p) {
  os<<"Name: "<<p.name<<", Number: "<<p.number<<", Points: "<<p.points;
  return os;
}
PlayerData parse(const std::string& line) {
  PlayerData data;  
  std::stringstream ss(line);  
  std::vector<std::string> tokens;
  std::copy(std::istream_iterator<std::string>(ss),
            std::istream_iterator<std::string>(),
            std::back_inserter<std::vector<std::string>>(tokens));
  data.points = std::stoi(tokens.at(tokens.size() - 1));
  data.number = std::stoi(tokens.at(tokens.size() - 2));
  for(auto it=tokens.begin(); it!=tokens.end()-2; ++it) {
    data.name.append(" ");
    data.name.append(*it);
  }
  return data;
}
int main(int argc, char* argv[]) {
  std::string line;
  std::vector<PlayerData> players;  
  { // scope for fp                                    
    std::ifstream fp(argv[1], std::ios::in);
    while(!fp.eof()) {
      std::getline(fp, line);
      if(line.size()>0) {
        players.push_back(parse(line));
      }
    }
  } // end of scope for fp
  // print list of players, or do whatever you want with it.
  for(auto p:players) {
    std::cout<<p<<std::endl;    
  }
  return 0;
}

使用支持c++ 11的g++版本进行编译(在我的例子中是gcc 4.7.2)。

[Prompt] g++ -oparseline parseline.cpp -std=c++11 -O2
[Prompt] ./parseline players.txt
Name:  Fernando Torres, Number: 9, Points: -29
Name:  Cristiano Ronaldo, Number: 7, Points: 31
Name:  Wayne Rooney, Number: 10, Points: 37
Name:  Neymar, Number: 17, Points: 29
Name:  Andres Iniesta, Number: 8, Points: 32
Name:  Robin van Persie, Number: 19, Points: 20
Name:  Lionel Messi, Number: 10, Points: 43
Name:  Xavi Hernandez, Number: 6, Points: 36
Name:  Mesut Özil, Number: 10, Points: 38
Name:  Didier Drogba, Number: 10, Points: 35
Name:  Fernando Torres, Number: 9, Points: 29
Name:  Kaká, Number: 10, Points: 17