在矢量中查找对象时出错

Error in finding object in vector

本文关键字：对象 出错 查找      更新时间：2023-10-16

我有一个Point类，我通过做Point p(a, b)来创建每个对象，我想找到点是否存在于我声明为vector<Point> vPoint的向量中。

我的一段代码如下;

Point p(a, b);
vector<Point>::iterator it = find(vPoint.begin(), vPoint.end(), p);
if(it != vPoint.end())
{
   // do something
}

我得到的错误信息如下;

中包含的文件
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/iostream:38:
In file included from /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/ios:216:
In file included from /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/__locale:15:
In file included from /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/string:439:
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/algorithm:846:22: error: 
      invalid operands to binary expression ('Point' and 'const Point')
        if (*__first == __value_)
            ~~~~~~~~ ^  ~~~~~~~~
segmentpoints.cpp:72:33: note: in instantiation of function template specialization 'std::__1::find<std::__1::__wrap_iter<Point
      *>, Point>' requested here
                        vector<Point>::iterator it = find(vPoint.begin(), vPoint.end(), p);
                                                     ^
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/utility:403:1: note: 
      candidate template ignored: could not match 'pair<type-parameter-0-0, type-parameter-0-1>' against 'Point'
operator==(const pair<_T1,_T2>& __x, const pair<_T1,_T2>& __y)
^
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/iterator:574:1: note: 
      candidate template ignored: could not match 'reverse_iterator<type-parameter-0-0>' against 'Point'
operator==(const reverse_iterator<_Iter1>& __x, const reverse_iterator<_Iter2>& __y)
^
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/iterator:866:6: note: 
      candidate template ignored: could not match 'istreambuf_iterator<type-parameter-0-0, type-parameter-0-1>' against 'Point'
bool operator==(const istreambuf_iterator<_CharT,_Traits>& __a,

所以我想知道这个问题是否由于在创建对象/迭代器时不使用指针而不支持指针指向的对象，或者其他什么。

c++不会自动创建比较运算符，因此您必须定义两点相等的含义。例如，一个合理的实现可以是:

bool operator==(const Point& a, const Point& b) {
    return a.x == b.x && a.y == b.y;
}

还请注意，如果您的代码需要它，您还必须实现operator !=，因为如果给定==, c++不会自动实现!=，反之亦然。

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