我的for循环中的getline和cout语句被截断了

My getline and cout statement within my for loop are being truncated

本文关键字：语句 cout 循环 for getline 我的      更新时间：2023-10-16

对于这段代码，它会询问第一首歌曲，并存储和打印它。但在第一个条目之后，我会被问到是否会像我想要的那样撒谎继续，但在我键入Y之后，它会跳过我的歌曲问题和getline函数，直接问我是否想继续，我在这里做错了什么？

这是我的输出

输入歌曲的名称。我需要帮助
是否要继续(y/n(？y
输入歌曲的名称。是否要继续(y/n(？y
输入歌曲的名称。是否要继续(y/n(？y
输入歌曲的名称。是否要继续(y/n(？n
共输入4首歌曲标题
我需要帮助

我想要的输出和期望的输出是

输入歌曲的名称。我需要帮助
是否要继续(y/n(？y
输入歌曲的名称。打印
是否要继续(y/n(？y
输入歌曲的名称。并输入
是否要继续(y/n(？y
输入歌曲的名称。这些歌曲
是否要继续(y/n(？n
共输入4首歌曲标题
我需要帮助
打印
并输入
这些歌曲

/*This program will ask a user to enter a song list. By doing this each time that the     user enters
a song, he/she will then be asked if they want to enter another song, if yes then they     will enter another song.There will be a maximum of 15 songs.
This progarm will help a user keep track of their songs. But then the program will     output the amount of songs, and what they are.
input:A song. Then a yes or no, if yes, another song, if no the program will output.
output:The number of songs, and then the songs themselves, each song with it's own     individual line.
processing: There will be two functions, one of which will ask the user for the songs and     store them, and another for which will be computing
the output.
*/
    #include<iostream>
    #include<string>
using namespace std;
int input(string[15], int);
void printArray(string[15], int);
int main()
{
    const int arraysize=15;
    string songarray[arraysize];
     int x=input(songarray, arraysize);

      cout<<"There were "<<x<<" song titles entered.n";
      printArray(songarray, x);
       return 0;
       }
/*This function will ask for the users input for a song and store the song in the     songarray. He or she
will then be asked whether or not they want to enter another song, if so, then they     will enter another song.
input:a song, y/Y or n/N for if they want to continue or not with another song
output:song will be sent to main function
processing: A while loop will be used for the user to enter is Y or N, and a for loop     (while loop nested) for the user to enter the 
songs
*/
int input(string titles[15], int rows)
{
      char answer='y';
      int k=0;
      for(int i=0;i<rows && (answer=='Y' || answer=='y');i++)
      {
           cout<<"Enter the name of a song. ";
           getline(cin, titles[i]);
           cout<<"Do you want to continue (y/n)? ";
           cin>>answer;
           k=i+1;
            }
           return k;
           }
/*The purpose of this function is to print the array from the main function.
input:accepts the array from the main function
output: prints the array
processing:nested loops will pring this array.
*/
void printArray(string playlist[15], int quantity)
{
    for(int j=0; j<quantity; j++)
    {
        cout<<playlist[j];
    }
}

问题是，您的"cin>>答案"读取单个字符，但您键入"y"，然后按enter键，因此换行符仍位于cin中。因此，当循环返回到getline时，只需读取换行符，最后得到一个空字符串。

如果你这样做：

string dummy;
getline(cin, dummy);

在"cin>>答案"之后，它将吃掉后面的换行符。

char answer;
cin >> answer;

问题确实存在：在cin.ignore中查找另一个解决方案

char answer;
cin >> answer;

你按了哪些键来回答程序的问题？哪一个最终进入answer？哪一个保留在stdin中，在键入其他内容之前终止下一个getline？

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