在通过组合传递对象数组时使用构造函数

Using constructor when passing an array of objects through composition

本文关键字：数组构造函数对象组合更新时间：2023-10-16

#include <iostream>
#include <cstring>
using namespace std;
class assistantnurse{
private:
    char* id;
    char dutytime;
public:
    assistantnurse(char[] ="", char =' ');
    void setid(char*);
    void setdutytime(char);
    char* getid()const;
    char getdutytime()const;
    void print()const;
    void inputinfo();
    ~assistantnurse();
};
assistantnurse::~assistantnurse()
{
    delete[] id;
    id=0; 
}
assistantnurse::assistantnurse(char* i, char t)
{
    setid(i);
    setdutytime(t);
}
void assistantnurse::setid(char *i)
{
    int l=strlen(i);
    id=new char[l+1];
    strncpy(id,i,l);
    id[l]='';
}
void assistantnurse::setdutytime(char t)
{
    dutytime=t;
}
char* assistantnurse::getid()const{return id;}
char assistantnurse::getdutytime()const{return dutytime;}
void assistantnurse::print()const
{
    cout<<"ID: "<<id<<endl;
    cout<<"Duty time: "<<dutytime<<endl<<endl;
}

void assistantnurse::inputinfo()
{
    char nurseid[20];
    char time;
    cout<<"Enter nurse ID: ";
    cin>>nurseid;
    do
    {
    cout<<"Enter nurse Duty time(d for day/n for night): ";
    cin>>time;
    }while(time!='n' && time!='d');
    setid(nurseid);
    setdutytime(time);
}
class treatingphysician{
private:
    char* id;
    char* phonenumber;
    assistantnurse assistant[2]; //3 assistant nurses through composition from assistantnurse class
public:
    void setid(char*);
    void setphonenumber(char*);
    char* getid()const;
    char* getphonenumber()const;
    void setnurse();
    void getnurse()const;
    treatingphysician(char[] =" ", char[] =" ", assistantnurse[]);
    ~treatingphysician();
    void print()const;
    void inputinfo();
};
void treatingphysician::inputinfo()
{
    char i[20];
    char p[15];
    cout<<"Enter physician ID: ";
    cin>>i;
    setid(i);
    cout<<"Enter physican phone number: ";
    cin>>p;
    setphonenumber(p);

    setnurse();

}
void treatingphysician::print()const
{
    cout<<"Physician ID: "<<id<<endl;
    cout<<"Physician phone number: "<<phonenumber<<endl<<endl;
    getnurse();
}
treatingphysician::~treatingphysician()
{
    delete[] id;
    id=0;
    delete[] phonenumber;
    phonenumber=0;
}

 treatingphysician::treatingphysician(char*i, char*p, assistantnurse k[2]):assistant(k)
{
    setid(i);
    setphonenumber(p);
}
void treatingphysician::setid(char*i)
{
    int l=strlen(i);
    id=new char[l+1];
    strncpy(id,i,l);
    id[l]='';
}
void treatingphysician::setphonenumber(char*p)
{
    int l=strlen(p);
    phonenumber=new char[l+1];
    strncpy(phonenumber,p,l);
    phonenumber[l]='';
}
char* treatingphysician::getid()const{return id;}
char* treatingphysician::getphonenumber()const{return phonenumber;}
void treatingphysician::setnurse()
{
    for(int i=0;i<3;i++)
    {
        cout<<"Enter info for nurse #"<<i+1<<endl;
        assistant[i].inputinfo();
        cout<<"n";
    }
}
void treatingphysician::getnurse()const
{
    for(int i=0;i<3;i++)
    {
        cout<<"Nurse #"<<i+1<<" ";
        assistant[i].print();
    }
}

int main()
{
    treatingphysician e;
    e.inputinfo();
    e.print();

    system("pause");
    return 0;
}

两类;护士班和医生班;医生有三个护士和他所有的特质。使用合成来修复这个问题，但我被困在3个护士的对象数组上。

在我的第二个构造函数中，我遇到了一个问题，我以前用同样的方法处理复合，但唯一的区别是它不是复合中使用的对象数组。现在我被困住了…请帮助

短例子…

"类{

公众:();

};

B类{私人:[2],

公众:B ([]);

};

B: B (c [2]): (c){}"

使用std::vector代替原始数组

class A
{
    public: 
        A(); 
};
typedef std::vector< A > A_vector;

class B
{ 
    private: 
    A_vector m_a;    
    public: 
    B( A_vector av ) : m_a( av )
    {
    }
};