c++将_bstr_t转换为int并将int转换为_bstr_t

c++ convert _bstr_t to int and convert int to _bstr_t

本文关键字：int 转换 bstr 并将 c++      更新时间：2023-10-16

我遇到了一个问题，这是我的代码，

          _bstr_t bstrTrans=L"2";
    wsprintf(buf,L"insert into inven(ID) values(%s)",(wchar_t *)bstrTrans)//insert into database
//this can work fine, now we want to let bstrTrans add 1, likes this
            int bstrTrans2 = atoi(bstrTrans) + 1;
    wsprintf(buf,L"insert into inven(ID) values(%s)",(wchar_t *)bstrTrans2 )
// now ,it cannot work.

有谁能帮我吗?

为什么不简单的s -> d呢?

    _bstr_t bstrTrans=L"2";
    wsprintf(buf,L"insert into inven(ID) values(%s)",(wchar_t *)bstrTrans) 
//insert into database
//this can work fine, now we want to let bstrTrans add 1, likes this
    int bstrTrans2 = atoi(bstrTrans) + 1;
    wsprintf(buf,L"insert into inven(ID) values(%d)",bstrTrans2 )

编辑:嗯，这个工作?

    _bstr_t bstrTrans=L"2";
    wsprintf(buf,L"insert into inven(ID) values(%s)",(wchar_t *)bstrTrans) 
//insert into database
//this can work fine, now we want to let bstrTrans add 1, likes this
    char t[30];
    bstrTrans = itoa ( atoi (bstrTrans) + 1 , t,10);
    wsprintf(buf,L"insert into inven(ID) values(%s)",(wchar_t *)bstrTrans)

未测试，但应该可以正常工作:

const _wchar_t pBuffer[16] = {0};
wsprintf(pBuffer, L"%u", bstrTrans2)
_bstr_t bstrTrans3(pBuffer);
wsprintf(buf,L"insert into inven(ID) values(%s)",(wchar_t *)bstrTrans3 );
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