C++基本继承
C++ basic inheritance
在学习C++类 - 基本继承时,我的程序返回了一个错误:"C++禁止指针和整数之间的比较,C++禁止指针和整数之间的比较"。 我哪里做错了? 感谢您的帮助!:-)
#include <iostream>
using namespace std;
class Pizza
{ public: int slices; char topping[10]; bool pepperoni , cheese ; };
int main() {
// Make your own Pizza!
Pizza pizza;
cout << "n You can have Cheese or Pepperoni Pizza!";
cout << "n Type [cheese] or [pepperoni] n";
cin >> pizza.topping[10];
if (pizza.topping[10] == "pepperoni") { pizza.pepperoni = true;}
if (pizza.pepperoni == true) {cout << "How many slices of pepperoni would you like?";};
if ( pizza.topping[10] == "cheese") { pizza.cheese = true;}
if (pizza.cheese == true) {cout << "How many slices of cheese would you like?";};
cin >> pizza.slices;
if (pizza.slices >= 1) {cout << "You ordered " << pizza.slices << " slices of " << pizza.topping[10] << " Pizza!"; }
else if (pizza.slices <= 0) {cout << "Change your mind?"; }
else { cout <<"Can't Decide? That's Okay.";}
}
在这里:
pizza.topping[10] == "pepperoni"
topping[10]
是 char
型,而"pepperoni"
是衰减到 const char*
的字符数组。您无法比较这两种类型。
如果你想将顶部的字符串与"意大利辣香肠"进行比较,那么你应该使用例如:
if (strcmp(pizza.topping, "pepperoni") == 0 ) {}
在C ++中,你应该使用std::string
这将使你的生活更轻松。
顺便说一句,正如评论中所述,topping[10]
是越界的,这是未定义的Behaiour,比编译错误更糟糕的事情。还要确保顶部的任何字符串都以"\0"字符结尾
感谢您的所有回复:-(程序有效!
// C++ Class - Basic Inheritance - User Inputs Values
#include <iostream>
using namespace std;
class Pizza
{ public: int slices; string topping; bool pepperoni=false, cheese=false ; };
int main()
{
// Make your own Pizza!
Pizza pizza;
cout << "n You can have Cheese or Pepperoni Pizza!";
cout << "n Type [cheese] or [pepperoni] n";
cin >> pizza.topping;
if (pizza.topping == "pepperoni") { pizza.pepperoni = true;}
if (pizza.pepperoni == true) {cout << "How many slices of pepperoni would you like?";
cin >> pizza.slices; }
else if ( pizza.topping == "cheese") { pizza.cheese = true;}
if (pizza.cheese == true) {cout << "How many slices of cheese would you like?";
cin >> pizza.slices; }
if (pizza.slices >= 1) {cout << "You ordered " << pizza.slices << " slices of " << pizza.topping << " Pizza!"; }
else if (pizza.slices <= 0) {cout << "Change your mind?"; }
else { cout <<"Can't Decide? That's Okay.";}
}
相关文章:
- 继承函数的重载解析
- 继承期间显示未知行为的子类
- 头文件-继承c++
- 为什么在保护模式下继承升级不起作用
- 通过继承类使用来自不同命名空间的运算符
- 子目录是否继承属性,例如add_definitions,include_directories和父Cmakelist.t
- 混合组合和继承的C++问题
- 继承:构造函数,初始化C++11中基类的类C数组成员
- 从类继承时,继承的类是否会通过父类重新定义继承的变量
- 公共与私人继承
- 如何创建从同一类继承的不同对象的向量
- 如何从另一个文件继承私有成员变量和公共函数
- 在模板基类中为继承类中的可选重写生成虚拟方法
- 带有继承的C++工厂
- 我应该避免多重实现继承吗
- C++继承更改成员
- 从具有默认值的部分指定模板类继承时发生SWIG错误,具有不带默认值的正向声明
- 关于C++中具有多重继承"this"指针的说明
- 尝试使用继承和模板实现CRTP.Visual Studio正在生成编译器错误
- 如何在QT Creator上将QWidget声明为继承类的对象