C++Integer从*char[]中删除字符串

我正试图在C++程序中读入几个值。

当我输入一个1位数的数字（在我的代码底部）时，我就没事了。

但是，如果我输入一个2位数的数字，比如"10"，消息（我输入的第二个数字）就会被擦除。

这是我的代码：

char * args[6];
unsigned time = 5;
char input[5];   // for string input
string message= "message";
//these strings and *chars are tempary strings for the purpose of reading in data
string temp;
char *temp2 = " ";
char *temp3 = "empty pointer";
     args[count] = "-m";
    count ++;
    //Prompt for the message
    cout <<endl<<"Alright, Please enter your message: "<<flush;
    getline(cin, message);
    cout <<endl<<endl;
    message.append(""");
    message = """+message;
    //we can't use the string, so we copy it to temp3.
    strcpy(temp3, message.c_str());
    //Now we input the string into our array of arguments
    args[count] = temp3;
    count ++;

    cout <<"Please enter time  "<<flush;
    getline(cin,temp);
    //validate input utnil its an actual second.
    bool done = false;
    while (done == false){
        for(unsigned i = 0; i < temp.length() & i < 5; i++){
            input[i] = temp[i];
        }
    done = CheckInteger(input, input);
        time = atoi(input);
        if (done == true & time < 1) {
            cout <<"Unable to use a number less than 1 seconds!  "<<endl;
            cout <<"Please enter the number of seconds?  "<<flush;
            done = false;
        }else if (done == false){
            cout <<"Please enter the number of seconds?  "<<flush;
        }else{
        break;
        }
        getline(cin,temp);
    }
    cout <<endl<<endl;
    time = atoi(input);
    //timer argument
    args[count] = "-t";
    count ++;
    // enter the time need to comvert from int to string.
    ostringstream convert;
    convert <<time;
    temp = convert.str();
    //need to convert from string to character
    strcpy(temp2, temp.c_str());
    args[count] = temp2;
    count ++;

我该怎么解决这个问题？