如何更正收银机程序的输出?

编写一个C++程序来计算收银机抽屉里的现金。 你要在抽屉里数每个面额的钞票的编号。 调用一个函数，通过接受面额和钞票数量并返回金额来确定每种面额的金额。该函数还可以接受每个面额的硬币数量和硬币的数量并返回金额。

你的程序应该写每个面额，纸币/硬币的数量， 每个金额和抽屉中的总金额。

同时写入屏幕和输出数据。格式为：

Denomination    Number  Amount
------------------------------
.
.
.
.
.
.
.
------------------------------
Total           $

int main() {
setprecision (2);
string d;
int t;
int tpenny;
int tnickel;
int tdime;
int tquarter;
int tone;
int tfive;
int tten;
int ttwenty;
int tfifty;
int thundred;
double penny;
double nickel;
double dime;
double quarter;
double one;
double five;
double ten;
double twenty;
double fifty;
double hundred;
cout << "Enter denomination and amount of bills/coins" << endl;
cout << "(i.e. 'penny 5' = 0.05c, 'quarter 3' = 0.75c, 'twenty 2' = $40.00)" << endl;
cout << "When all amounts have been entered, enter 'done'" << endl;
while (d != "done") {
double total = penny + nickel + dime + quarter + one + five + ten + twenty + hundred;
cin >> d;
if (d == "done") {
cout << "Denomination     " << "Number     " << "Amount" << endl;
cout << "-----------------------------------" << endl;
cout << "Penny:             " << tpenny << "         " << "$" << penny << endl;
cout << "Nickel:            " << tnickel << "         " << "$" << nickel << endl;
cout << "Dime:              " << tdime << "         " << "$" << dime << endl;
cout << "Quarter:           " << tquarter << "         " << "$" << quarter << endl;
cout << "One:               " << tone << "         " << "$" << one << endl;
cout << "Five:              " << tfive << "         " << "$" << five << endl;
cout << "Ten:               " << tten << "         " << "$" << ten << endl;
cout << "Twenty:            " << ttwenty << "         " << "$" << twenty << endl;
cout << "Fifty:             " << tfifty << "         " << "$" << fifty << endl;
cout << "Hundred:           " << thundred << "         " << "$" << hundred << endl;
cout << "-----------------------------------" << endl;
cout << "Total:                       " << "$" << total << endl;
}
else {
cout << "Enter additional currency. (if done, type 'done')" << endl;
cin >> t;
if (d == "penny") {
tpenny = t;
penny = value (d, t);
}
if (d == "nickel") {
tnickel = t;
nickel = value (d, t);
}
if (d == "dime") {
tdime = t;
dime = value (d, t);
}
if (d == "quarter") {
tquarter = t;
quarter = value (d, t);
}
if (d == "one") {
tone = t;
one = value (d, t);
}
if (d == "five") {
tfive = t;
five = value (d, t);
}
if (d == "ten") {
tten = t;
ten = value (d, t);
}
if (d == "twenty") {
ttwenty = t;
twenty = value (d, t);
}
if (d == "fifty") {
tfifty = t;
fifty = value (d, t);
}
if (d == "hundred") {
thundred = t;
hundred = value (d, t);
}
}
}
return 0;
}

我目前编写代码的方式有效，但前提是为每种货币输入一个值。例如，如果我不输入 5 的值，则我的 Amount 是某个疯狂的数字，而 Number 的默认值不是 0。

您对如何解决此问题有任何想法吗？值也是一个函数，它读取一个字符串和一个整数(即便士 5)并返回货币值。