变得奇怪

我目前正在学习C 中的功能，目前正在从事功能为主要方面的作业。

当前，我正在尝试将整个过程的每个操作分为自己的函数。

这是代码：

#include <iostream>
#include <fstream>
#include <string>
#include <stdlib.h>
using namespace std;
void getHWGrades(int homeworks[], int size)
{
    cout << "nEnter the grades, out of 100 points, for the 9 homeworks you completed." << endl;
    cout << "Note that Homework 10 is given to you for free, but is the same grade nas homework 9.n" << endl;
    for (int i = 0; i < 9; i++)
    {
        cout << "Homework " << i + 1 << ": ";
        cin >> homeworks[i];
        while (homeworks[i] > 100 || homeworks[i] < 0)
        {
            cout << "Invalid grade, input homework grade again: ";
            cin >> homeworks[i];
        }
    }
    homeworks[9] = homeworks[8];
    cout << "Homework 10: " << homeworks[9];
}
double quizAverage()
{
    double quizPts;
    cout << "Input your in class quiz average: ";
    cin >> quizPts;
    return quizPts;
}
double labAverage()
{
    double labPts;
    cout << "Input your lab average: ";
    cin >> labPts;
    return labPts;
}
double teamProject()
{
    double teamPts;
    cout << "Input your team project grade: ";
    cin >> teamPts;
    return teamPts;
}
int exam1()
{
    int exam1Pts;
    cout << "Input your exam1 grade: ";
    cin >> exam1Pts;
    return exam1Pts;
}
int exam2()
{
    int exam2Pts;
    cout << "Input your exam2 grade: ";
    cin >> exam2Pts;
    return exam2Pts;
}
double hwAverage(int homeworks[], int size)
{
    double total = 0;
    double homeworkAverage = 0;
    for (int i = 0; i < size; i++)
    {
        total = total + homeworks[i];
    }
    homeworkAverage = (total*1.0) / 10;
    return homeworkAverage;
}

double currentPoints(double& quizPts, double& labPts, double& teamPts, double& homeworkAverage, int& exam1Pts, int& exam2Pts)
{
    double totalPts = ((quizPts / 100.0) * 10) + ((labPts / 100.0) * 10) + ((teamPts / 100.0) * 15) + ((homeworkAverage / 100.0) * 20) + ((exam1Pts / 100.0) * 10) + ((exam2Pts / 100.0) * 15);
    cout << "nYour current points (out of the 80 total available), stand at: " << totalPts;
    return totalPts;
}
double currentAverage(double& totalPts)
{
    double availableAverage = totalPts*(100.0 / 80);
    cout << "nYour current average is: " << availableAverage;
    return availableAverage;
}
int main()
{    
    // keep the console from closing in visual studio
    char charer;
    double totalPts;
    double quizPts, labPts, teamPts, homeworkAverage;
    int exam1Pts, exam2Pts;
    const int ARRAY_SIZE = 10;
    int hwArray[ARRAY_SIZE];
    getHWGrades(hwArray, ARRAY_SIZE);
    quizAverage();
    labAverage();
    teamProject();
    exam1();
    exam2();
    currentPoints(quizPts, labPts, teamPts, homeworkAverage, exam1Pts, exam2Pts);
    currentAverage(totalPts);
    cin >> charer;
}

我认为，我的问题在于函数currentPoints和currentAverage，是当我运行此totalPts以-5.09078e+61输出时，并且作为currentAverage函数的后续结果，availableAverage输出为-1.157e+62。

我敢肯定，问题与我如何将值从函数传递到函数（我怀疑我正确地执行）有关。

我将如何解决此问题？

预先感谢您。