C 复制构造函数当类具有另一个类的数组时

我仍在学习课程，复制构造函数和超载运算符，以便任何建议/帮助/-> s受到赞赏!!!

我试图用类Test2制作一个复制构造函数，该类别具有来自另一个类Test1的私有成员变量。我已经在代码中评论了给我业务所在的复制构造函数。

这是我在编译时遇到的错误：

assOp.cpp: In copy constructor 'Test2::Test2(const Test2&)':
assOp.cpp:102:25: error: passing 'const Test2' as 'this' argument of 'int Test2:
:getNum()' discards qualifiers [-fpermissive]
  setNum(original.getNum());
                         ^
assOp.cpp:103:27: error: passing 'const Test2' as 'this' argument of 'char* Test
2::getChar()' discards qualifiers [-fpermissive]
  setChar(original.getChar());

这是代码：

#include <iostream>
#include <cstring>
using namespace std;
class Test1
{
    public:
        Test1();
        Test1(const Test1& original);
        int getNum();
        char *getChar();
        void setNum(int x);
        void setChar(char y[]);

    private:
        int num;
        char *ch;
};
class Test2
{
    public:
        Test2();
        Test2(const Test2& original);
        void setNum(int x);
        void setChar(char y[]);
        int getNum();
        char *getChar();
    private:
        Test1  foo;

};
int main()
{
    Test1 a;
    Test2 b;

    return 0;
}
Test1::Test1()
{
    num = 1234;
    ch = new char[5];
    strcpy(ch,"test");
}
Test1::Test1(const Test1& original)
{
    int length = strlen(original.ch); 
    num = original.num;
    ch = new char[length + 1];
    strcpy(ch, original.ch);
    ch[length] = '';
}
int Test1::getNum()
{
    return num;
}
char *Test1::getChar()
{
    return ch;
}
void Test1::setNum(int x)
{
    num = x;
}
void Test1::setChar(char y[])
{
    int length = strlen(y); 
    ch = new char[length + 1];
    strcpy(ch, y);
    ch[length] = '';
}
Test2::Test2()
{
}
//Sassy copy constructor that thinks its better than me
Test2::Test2(const Test2& original)
{
    setNum(original.getNum());
    setChar(original.getChar());

}
void Test2::setNum(int x)
{
    foo.setNum(x);
}
void Test2::setChar(char y[])
{
    foo.setChar(y);
}
int Test2::getNum()
{
    return foo.getNum();
}
char *Test2::getChar()
{
    return foo.getChar();
}
                       ^