在冒险游戏中检查空房间

我正在为一个C++项目开发冒险游戏。目标基本上是拥有一堆由类定义的房间。然后使用地图将它们全部链接在一起。除了检查是否有空间并确保没有为空房间输入之外，我什么都工作。例如，它会说"那里什么都没有"，然后重新要求用户移动方向。目前，如果某个方向上没有空间并且选择了该方向，我的程序就会崩溃。我目前已对其进行设置，至少确保输入了有效的方向（北、南、东或西），但它甚至没有检查该方向是否可用。有人知道一个好方法吗？

主.cpp

    #include <iostream>
    #include <string>
    #include <map>
    #include "room.h"
    using namespace std;
    int main()
    {
        /* ---------- Variable Declerations ---------- */
        string exitChoice;
        /* ---------- Room Intialization ---------- */
        room *kitchen = new room("Kitchen", "You are in the Kitchen. Pots and pans dangle above your head as you look across the room.");
        room *diningRoom = new room("Dining Room", "You are in the Dining Room. You see a large table in the center of the room complete with a set of chairs. It seems no one has ate here in quite som time.");
        room *garage = new room("Garage", "You are in the Garage. There are tools spread across the concerte floor complete with a Jeep Grand Cherokee on jack stands.");
        room *masterBed = new room("Master Bed Room", "You are in the Bed Room. A large Master Bed greets you as you walk into the room. You can see a large master bath as weel in the backround");
        room *hallway = new room("Hallway", "You are in the Hallway. A large set of stairs leads to the second floor, complete with a set to the basement. You also see a grand front door.");
        room *familyRoom = new room("Family Room", "You are in the Family Room. You see a dark leather couch in front of you as well as a brand new LCD TV. It aappears South Park is on TV.");
        room *bathRoom = new room("Bath Room", "You are in the Bath Room. A small room containing just a toilet is in front of you.");
        room *frontLawn = new room("Front Lawn", "You are in the Front Lawn. You are on a pathway and observe freshly cut grass as well as several trees scattered across the yard.");
        room *backLawn = new room("Back Lawn", "You are in the Back Lawn. You see 'Spot' running around chasing a tennis ball, as well as his dog house. A large wooden fence keeps him in the yard.");
        /* ----------Room Links---------- */
        /* Kitchen */
        kitchen->link(diningRoom, "North");
        kitchen->link(garage, "East");
        kitchen->link(masterBed, "South");
        kitchen->link(hallway, "West");
        /* Dining Room */
        diningRoom->link(kitchen, "South");
        diningRoom->link(familyRoom, "West");
        /* Master Bed Room */
        masterBed->link(kitchen, "North");
        masterBed->link(bathRoom, "West");
        /* Garage */
        garage->link(kitchen, "West");
        garage->link(backLawn, "East");
        /* Back Lawn */
        backLawn->link(garage, "West");
        /* Family Room */
        familyRoom->link(diningRoom, "East");
        familyRoom->link(hallway, "South");
        /* Hallway */
        hallway->link(familyRoom, "North");
        hallway->link(kitchen, "East");
        hallway->link(bathRoom, "South");
        hallway->link(frontLawn, "West");
        /* Front Lawn */
        frontLawn->link(hallway, "East");
        /* Bath Room */
        bathRoom->link(hallway, "North");
        bathRoom->link(masterBed, "East");
        /* ----------Gameplay---------- */
        room *currentRoom = kitchen;
        while (exitChoice != "quit")
        {
            currentRoom->printRoom();
            cout << endl;
            currentRoom->printLiked();
            cout << "Which exit? (Or 'quit'):";
            cin >> exitChoice;
            if(exitChoice != "quit" && exitChoice != "North" && exitChoice != "South" && exitChoice != "East" && exitChoice != "West")
            {
                cout << "Invalid Entry!" << endl;
                cout << "Which exit? (Or 'quit'):";
                cin >> exitChoice;
            }
            cout << "You move to the " << exitChoice << "..." << endl;
            currentRoom->getLinked(exitChoice);
            currentRoom = currentRoom->getLinked(exitChoice);
        }
    }

房间.h

#ifndef ROOM_H
#define ROOM_H
using namespace std;
#include <string>
#include <iostream>
#include <map>
class room
{
    private:
        string name;
        string description;
    public:
    /* Constructor Prototypes */
    room(string, string);
    room(string);
    /* Get Name */
    string getName()
    {
        return name;
    }
    /* Get Description */
    string getDescription()
    {
        return description;
    }
    /* Print Room Information */
    void room :: printRoom()
    {
        cout << "--" << getName() << "--" << endl;
        cout << getDescription() << endl;
    }
    /* Map */
    map<string, room*> exits;
    /* Link Function*/
    void link(room *room, string direction)
    {
        exits[direction] = room;
    }
    /* Print Linked Rooms */
    void printLiked()
    {
        map<string, room*> :: iterator it;
        cout << endl;
        for(it = exits.begin(); it != exits.end(); ++it)
        {
            cout << "Exit: ";
            cout << it->first << " (" << it->second->getName() << ")" << endl;
        }
        cout << endl;
    }
    /* Get linked room */
    room* getLinked(string direction)
    {
        map<string, room*> :: iterator it;
        it = exits.find(direction);
        if(it != exits.end())
        {
            return it->second;
        }
        else
        {
            return NULL;
        }

    }


};
#endif

房间.cpp

 #include <iostream>
    #include <string>
    #include <map>
    using namespace std;
    #include "room.h"
        /* Constructor with Name and Description */
        room :: room(string _name, string _description)
        {
            name = _name;
            description = _description;
        }

        /* Contrsuctor with Name */
        room :: room(string _name)
        {
            name = _name;
        }

新主.cpp狙击

        room* possibleNewRoom = currentRoom->getLinked(exitChoice);
        if (possibleNewRoom != 0)
        {
            currentRoom = possibleNewRoom;
            cout << "You move to the " << exitChoice << "..." << endl;
            currentRoom->getLinked(exitChoice);
            currentRoom = currentRoom->getLinked(exitChoice);
        }
        else
        {
            cout << "There are no exits in that direction." << endl;
        }