runge-kutta第四阶集成器的错误

Error with Runge-Kutta 4th order integrator

本文关键字:错误 集成 runge-kutta      更新时间:2023-10-16

我一直在处理第四阶runge-kutta求解器,并且遇到了一些困难。我已经根据有关Gafferongames的文章编写了求解器,但是当我运行一个较小的示例时,即使是简单的重力力量,我所遇到的错误远比我通过简单的Euler集成所获得的错误要差得多。我已经将其整理成一个自我包含的示例(包括打印在内的代码约60行),但需要GLM运行。
它显示了我的整体问题。第55行打印出分析解决方案和RK4解决方案之间的差异。这应该相对较小,但是即使在采取10个奇数步骤之后,它也会爆炸。

#include <iostream>
#include <glm/glm.hpp>
struct State{
    glm::vec3 position, velocity;
};
class Particle{
public:
    glm::vec3 position, velocity, force;
    float mass;
    void solve(float dt);
    glm::vec3 acceleration() const {return force/mass;}
    State evalDerivative(float dt, const State& curr);
    void analytic(float t,  glm::vec3 a);
};
int main(int argc, char* argv[]){
    Particle p;
    p.position = glm::vec3(0.f);
    p.mass = 1.0f;
    for(int i = 1; i <= 10; i++)    {
        p.force = glm::vec3(0.f, -9.81f, 0.f);
        p.solve(.016f);
        p.analytic(i*.016f, glm::vec3(0.f, -9.81f, 0.f));
    }
    getchar();
    return 0;
}
void Particle::solve(float dt){
    State t;t.position = glm::vec3(0.f); t.velocity = glm::vec3(0.f);
    State k1 = evalDerivative(0, t);
    State k2 = evalDerivative(dt*.5f, k1);
    State k3 = evalDerivative(dt*.5f, k2);
    State k4 = evalDerivative(dt, k3);
    position += (k1.position + 2.f*(k2.position + k3.position) + k4.position)/6.f;
    velocity += (k1.velocity + 2.f*(k2.velocity + k3.velocity) + k4.velocity)/6.f;
    force = glm::vec3(0.f);
}
State Particle::evalDerivative(float dt, const State& curr){
    State s;
    s.position = position + curr.position*dt;
    s.velocity = velocity + curr.velocity*dt;
    s.position = s.velocity;
    s.velocity = acceleration();
    return s;
}
void Particle::analytic(float t, glm::vec3 a){
    glm::vec3 tPos = glm::vec3(0.f) + 0.5f*a*t*t;
    glm::vec3 tVel = glm::vec3(0.f) + a*t;
    glm::vec3 posdiff = tPos - position;
    glm::vec3 veldiff = tVel - velocity;
    std::cout << "POSITION: " << posdiff.x << ' ' << posdiff.y << ' ' << posdiff.z << std::endl;
    std::cout << "VELOCITY: " << veldiff.x << ' ' << veldiff.y << ' ' << veldiff.z << std::endl << std::endl;
}

如果有人可以帮助我在这里,我正处于这个结束时。

好吧,我感到很愚蠢。我一直在研究这个小时,我错过了一个小步骤:

position += (k1.position + 2.f*(k2.position + k3.position) + k4.position)/6.f;
velocity += (k1.velocity + 2.f*(k2.velocity + k3.velocity) + k4.velocity)/6.f;

应该是

position += (k1.position + 2.f*(k2.position + k3.position) + k4.position)*dt/6.f;
velocity += (k1.velocity + 2.f*(k2.velocity + k3.velocity) + k4.velocity)*dt/6.f;