C++ 替换<< >>分量之间的一组字符串

c++ replace a set of strings between << >> delimeters

本文关键字：lt gt 一组 字符串 之间 替换 分量 C++      更新时间：2023-10-16

我想替换<<>>分隔符之间的一组字符串。

例如说 

int age= 25;
string name= "MYNAME";
string test = My age is << your age >> and my name is << your name >>.

输出应为 

My age is 25 and my name is MYNAME.
最好的

方法是C ++？

试试这个 

#include <iostream>       
#include <string>        
int main ()
{
  std::string str ("My age is << your age >> and my name is << your name >>.");
  std::string str2 ("<< your age >>");
  std::string str3 ("<< your name >>");
  str.replace(str.find(str2),str2.length()," 22 ");
  str.replace(str.find(str3),str3.length()," Nooh ");
  std::cout << str << 'n';
  return 0;
}

我不确定我是否理解这个问题，但如果它是我认为的，请尝试

string test = "My age is " + age + " and my name is " + name + ".";

如果您执意要使用<<和>>，您可以

cout << "My age is " << age << " and my name is " << name << "." << endl;
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