保存元组_cat的结果

Saving the results of a tuple_cat

本文关键字：结果 cat 元组 保存      更新时间：2023-10-16

我有从另一个源代码。其余的代码运行良好。我正在尝试使用以下代码附加到元组：

// Because std::make_tuple can't be passed
// to higher order functions.
constexpr struct MakeTuple
{
    template< class ...X >
    constexpr std::tuple<X...> operator () ( X ...x ) {
        return std::tuple<X...>( std::move(x)... );
    }
} tuple{};
constexpr struct PushFront
{
    template< class ...X, class Y >
    constexpr auto operator () ( std::tuple<X...> t, Y y )
        -> std::tuple< Y, X... >
    {
        return std::tuple_cat( tuple(std::move(y)), std::move(t) );
    }
} pushFront{};
template <template <typename...> class T, typename... Args, typename... Obs>
T<Obs...> MakeSubject(std::tuple<Obs ...> &&obs, Args&& ... args)
{
    return T<Obs...>(std::move(obs), args...);
}
template <template <typename...> class T, typename... Args, typename... Obs>
std::tuple<T<Obs...>> Store(std::tuple<Obs ...> &&obs, Args&& ... args)
{
    return std::make_tuple(T<Obs...>(std::move(obs), args...));
}
template <typename Base> class Observer
{
}
class Printer : public Observer<Printer>
{
}
template <typename T, typename... Obs> class Subject
{
private:
    std::tuple<Obs &...> observers;
}
template <typename... Obs>
class Pressure : public Subject<Pressure<Obs...>, Obs...> 
{
}
std::ostream& operator << (std::ostream& out, const Printer& ac)
{
    //stuff
    return out;
}

我有这样一个循环外的代码：

const Printer sentinel; 
auto store = Store<Pressure>(std::move(std::tuple<Printer>(sentinel)), fakePressure); // The first one is just a delimiter

问题是，在循环中，当我试图通过说：来附加以存储元组时

while(true) // A Demo loop
{
    auto subject = MakeSubject<Pressure>(std::move(obs), q);
    pushFront(store, subject.Observers()));
    std::cout << store; // Always empty
    std::cout << pushFront(store, subject.Observers()); // This works and shows whatever I passed in, but the list of tuples doesn't grow from previous appends.
}

存储不会因为添加越来越多的std:：元组而增长。我希望元组的pushFront语义类似于std:：vector等的push_back。

有什么建议吗？

PushFront::operator()返回一个新元组，该元组后面跟有一个附加项，后面跟给定元组中的项。它不会附加到传入的。

由于N+1元素的tuple与N元素的tuple是不同的C++类型，因此不可能推入现有的类型。

相关文章：