奇怪的编译错误

有人能告诉我编译时错误的含义并帮助我解决吗？

这里有一个错误：

C： \doc1\collect2.exe[Error]ld返回1退出状态

这是文本文件：

 T(F)       R1        R2       R3        R4
 95.0     95.20     66.10     43.10     29.00
 96.0     96.10     67.60     43.50     31.20
 97.0     97.40     67.00     43.70     30.50
 98.0     97.20     69.10     44.10     30.70
 99.0     98.90     68.00     44.70     32.80
100.0    99.50     71.10     45.10     31.50
101.0   101.00     71.20     45.30     31.60
102.0   101.60     71.00     45.70     30.50
103.0   101.80     73.10     46.30     32.50
104.0   103.70     73.50     46.60     32.70
105.0   105.60     72.80     47.10     33.60

这是我的源

#include <fstream>
#include <iostream>
#include <string>
#include <iomanip>
#include <cmath>
#include <stdlib.h>
using namespace std;
void read ();
void slope(double,double,double,double,double,int,double);
void write(double,double,double,double,double,double);
double temp, R1, R2, R3, R4,rsq;
int main ()
{
    read();
    return 0;   
}
void read()
{
    ifstream indata("c:\doc1\temperaturedata.txt");
    int indx=0;
    if(indata == NULL)
    {
        cout<< "There is no file go get it from the CD"<< endl;
        return;
    }
    const int columns = 5;
    const int rows = 11;
    double Ihatearray[rows][columns];
    string temparature;
    getline(indata, temparature);
    for(int i = 0; i < rows; ++i)
    {
        for (int j = 0; j < columns; ++j)
            {
                cout << "t" << flush;
                indata >> Ihatearray[i][j];
                cout.setf(ios::fixed);
                cout << setprecision(2) << Ihatearray[i][j] <<flush;
            }
            cout << endl;
            double temp[20], R1[20],R2[20],R3[20],R4[20];
    }
    //indata.close();
    slope(temp, R1, R2, R3, R4,indx,rsq);
}
void slope(double x[5], double y[], double& m, double& b, int n,double& r)
{
    int i;
double xsum = 0., ysum = 0., xave, yave, x2sum = 0., y2sum = 0.,xysum =0.;
for(int i = 0; i < n; i++)
{
    xsum  += x[i];
    ysum  += y[i];
    x2sum += x[i] * x[i];
    y2sum += y[i] * y[i];
    xysum += x[i] * y[i];
}
xave=xsum/n;
yave=ysum/n;
m=(xysum-yave*xsum)/(x2sum-xave*xsum);
b=yave-m*xave;
r=(xysum-n*xave*yave)/(sqrt(x2sum-n*xave*xave)*sqrt(y2sum-n*yave*yave));
write (temp, R1, R2, R3, R4,rsq);
}
void write (double temp [], double R1[], double R2[], double R3[],double R4[],double
            rsq)
{
    //Where I will print out a table of the results.
}